Question

Triangle JKM with side j across from angle J, side k across from angle K, and side m across from angle M

Answer 1

Answer:

By the law of sins,

$\tt \frac{m}{sin40} =\frac{j}{sin45}$

$\tt m=\frac{7\times sin40}{sin45}$

$\tt =7\times \frac{0.6}{0.7} \times \frac{10}{10}$

$\tt = 0.6 \times 10$

$\tt =6.0$

Hope it helps!