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Nataly_w [17]
3 years ago
15

Let f(x)=2/x-3. Find f^-1(x)

Mathematics
1 answer:
KonstantinChe [14]3 years ago
7 0

Answer:

Two questions:

Question 1: f^{-1}(x)=? given f(x)=\frac{2}{x}-3.

Answer 1: f^{-1}(x)=\frac{2}{x+3}

Question 2: f^{-1}(x)=? given f(x)=\frac{2}{x-3}.

Answer 2: f^{-1}(x)=\frac{2}{x}+3

Step-by-step explanation:

So f^{-1} is used in most classes to represent the inverse function of f.

The inverse when graphed is a reflection through the y=x line. The ordered pairs (a,b) on f implies (b,a) are on f^{-1}.

This means we really just need to swap x and y.

Since we want to write as a function of x we will need to solve for y again.

Question 1:

y=\frac{2}{x}-3

Swap x and y:

x=\frac{2}{y}-3

We want to solve for y.

Add 3 on both sides:

x+3=\frac{2}{y}

Make the left hand side a fraction so we can cross-multiply:

\frac{x+3}{1}=\frac{2}{y}

Cross multiply:

y(x+3)=1(2)

Simplify right hand side:

y(x+3)=2

Divide both sides by (x+3):

y=\frac{2}{x+3}

So f^{-1}(x)=\frac{2}{x+3}.

Question 2:

y=\frac{2}{x-3}

Swap x and y:

x=\frac{2}{y-3}

Make left hand side a fraction so we can cross multiply:

\frac{x}{1}=\frac{2}{y-3}

Cross multiply:

(y-3)x=1(2)

We have to distribute here:

yx-3x=2

Add 3x on both sides:

yx=2+3x

Divide boht sides by x:

y=\frac{2+3x}{x}

You could probably stop here but you could also simplify a little.

Separate the fraction into two terms since you have 2 terms on top bottom being dividing by x:

y=\frac{2}{x}+\frac{3x}{x}

Simplify second fraction x/x=1:

y=\frac{2}{x}+3

So f^{-1}(x)=\frac{2}{x}+3.

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