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guapka [62]
2 years ago
11

Find the distance between the points (-10, 5) and (-8, -3). A) 2 17 B) 8 C) 59 D) 55

Mathematics
2 answers:
rjkz [21]2 years ago
8 0
Distance formula : sqrt ((x2 - x1)^2 + (y2 - y1)^2
(-10,5)....x1 = -10 and y1 = 5
(-8,-3)....x2 = -8 and y2 = -3
now sub
d = sqrt ((-8 - (-10)^2 + (-3 - 5)^2)
d = sqrt ((-8 + 10)^2 + (-8^2)
d = sqrt (2^2) + (-8^2)
d = sqrt (4 + 64)
d = sqrt 68
d = 8.25 <====
Serjik [45]2 years ago
5 0
You can use the distance formula.

The distance, d, between points (x1, y1) and (x2, y2) is

d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}

d = \sqrt{(-8 - (-10))^2 + (-3 - 5)^2}

d = \sqrt{2^2 + (-8)^2}

d = \sqrt{4 + 64}

d = \sqrt{68}

d = 8.24...

Answer:

B) 8
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Hey There!

The answer to your problem is x=-3 or x=-4 both answers are correct!

<u>Step 1: Subtract x²+12 from both sides.</u>

−7x−(x²+12)=x²+12−(x²+12)

−x²−7x−12=0

<u>Step 2: Factor left side of equation.</u>

(-x-3)(x+4)=0

<u>Step 3: Set factors equal to 0.</u>

-x-3=0 or x+4=0

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x=-3 or x=-4

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The correct answer for USATesprep is


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7 0
3 years ago
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Solve log6x+ log14=1
LekaFEV [45]

Answer:

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8 0
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Let x be the average number of employees in a group health insurance plan, and let y be the average administrative cost as a per
Step2247 [10]

A scatter diagram has points that show the relationship between two sets of data.

We have the following data,

\left\begin{array}{ccccccc}\mathrm{x}&3&7&15&32&74\\\mathrm{y}&40&35&30&25&17\end{array}\right

where <em>x</em> is the average number of employees in a group health insurance plan and <em>y</em> is the average administrative cost as a percentage of claims.

To make a scatter diagram you must, draw a graph with the independent variable on the horizontal axis (<em>in this case x</em>) and the dependent variable on the vertical axis (<em>in this case y</em>). For each pair of data, put a dot or a symbol where the x-axis value intersects the y-axis value.

Linear regression is a way to describe a relationship between two variables through an equation of a straight line, called line of best fit, that most closely models this relationship.

To find the line of best fit for the points, follow these steps:

Step 1: Find X\cdot Y and X\cdot X as it was done in the below table.

Step 2: Find the sum of every column:

\sum{X} = 131 ~,~ \sum{Y} = 147 ~,~ \sum{X \cdot Y} = 2873 ~,~ \sum{X^2} = 6783

Step 3: Use the following equations to find intercept a and slope b:

\begin{aligned}        a &= \frac{\sum{Y} \cdot \sum{X^2} - \sum{X} \cdot \sum{XY} }{n \cdot \sum{X^2} - \left(\sum{X}\right)^2} =             \frac{ 147 \cdot 6783 - 131 \cdot 2873}{ 5 \cdot 6783 - 131^2} \approx 37.05 \\ \\b &= \frac{ n \cdot \sum{XY} - \sum{X} \cdot \sum{Y}}{n \cdot \sum{X^2} - \left(\sum{X}\right)^2}        = \frac{ 5 \cdot 2873 - 131 \cdot 147 }{ 5 \cdot 6783 - \left( 131 \right)^2} \approx -0.292\end{aligned}

Step 4: Assemble the equation of a line

\begin{aligned} y~&=~a ~+~ b \cdot x \\y~&=~37.05 ~-~ 0.292 \cdot x\end{aligned}

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Mama L [17]
265 x 0.06 = 15.9

265 - 15.9 = 249.1

249.1 is your answer

hope this helps
3 0
3 years ago
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