Answer:
the width is 13.11meter and the length is 1.11meter
Step-by-step explanation:
let the width be x and the length be x-12
area = 160 = l×b = x×x-12
x×x-12 = 160
x^2 = 172
x= 13.11
thus, the width is 13.11 and the length is 1.11
Y=2(4)+8
y=8+8
y=16
Hope this helps :)
Answer:
2 touchdowns, 3 field goals
Step-by-step explanation:
The number of touchdowns cannot be more than 3, so it is relatively easy to find the solution by trial and error.
23 is not divisible by 3, so 0 touchdowns is not a solution
23 -7 = 16 is not divisible by 3, so 1 touchdown is not a solution
23 -14 = 9 is divisible by 3, so 2 touchdowns and 3 field goals is a solution
21 -21 = 2 is not divisible by 3, so there is only one solution.
let's plug the value of x and y as 5 and 4 respectively to find the value of given expression :