Help please I’ll give brianlest if it’s right

Mathematics

1 answer:

Bess [88]3 years ago

6 0

The top right “double sided” i’m pretty sure

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Find an exponential function that fits the information (hint: putting them in a table may help you see).

Vilka [71]

Answer:

f(x)=8*(3.5)^x

Step-by-step explanation:

2=98

3= 98r

4= 98r^2

5= 98r^3

6= 98r^4

98r^4/98, 98 crosses out and its just r^4. r^4= 14706.125/98

r=3.5

So you plug that in and you get f(x)=8*(3.5)^x

I hope this helped. XD

7 0

3 years ago

Consider a car owner who has an 80% chance of no accidents in a year, a 20% chance of being in a single accident in a year, and

steposvetlana [31]

Answer:

The expected loss for the car owner per year is $750.

Step-by-step explanation:

We are given that a car owner who has an 80% chance of no accidents in a year, a 20% chance of being in a single accident in a year, and no chance of being in more than one accident in a year.

Let X = Loss for the particular year for a car owner

Now as we know that the loss to the car owner may be of $0, $500, $5,000 or $15,000 because these amount he has to pay as a part of repair cost if his car met with an accident.

So, the probability distribution of X is given by;

X (Amount of Loss) P(X)

$0 0.80

$500 (0.20)(0.50) = 0.10

$5,000 (0.20)(0.40) = 0.08

$15,000 (0.20)(0.10) = 0.02

Total 1

Here, the probability of (0.20)(0.50) means that for the loss of $500, first the car must have to met with an accident and then there is 50% chance that after the accident the car will need repairs costing $500.

Now, the expected loss for the car owner per year is = $\sum (X \times P(X))$