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dybincka [34]
3 years ago
7

Which pair of measurements is not equivalent?

Mathematics
1 answer:
Bingel [31]3 years ago
6 0

Answer:

750 mm, 7.5 cm

Step-by-step explanation:

Verify each case

case a) 2.5 km, 2,500 m

we know that

1 km ------> 1.000 m

so

2.5 km=2,500 m

therefore

The pair of measurements is equivalent

case b) 750 mm, 7.5 cm

we know that

1 cm ------> 10 mm m

so

7.5 cm=75 mm

therefore

<u>The pair of measurements is not equivalent</u>

case c) 3 m, 3,000 mm

we know that

1 m ------> 1.000 mm

so

3 m=3,000 mm

therefore

The pair of measurements is equivalent

case d) 120 cm, 1.2 m

we know that

1 m ------> 100 cm

so

1.2 m=120 cm

therefore

The pair of measurements is equivalent

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Answer:

(i) the other two sides are 6 and  6\sqrt{2}

(ii) the other two sides are   \frac{4}{3} and                                         \frac{8}{3}

Step-by-step explanation:

(i)  Sine: sin(θ) = Opposite ÷ Hypotenuse

    Cosine: cos(θ) = Adjacent  ÷ Hypotenuse

    Tangent: tan(θ) = Opposite ÷ Adjacent

Here adjacent side = 6

opposite side = d

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other angles are 90° and 45°

tan (45) = Opposite ÷ Adjacent

 1 = d ÷ 6

∴ d = 6 × 1 = 6

so opposite side = 6

Hypotenuse ² = opposite side ² + adjacent side²

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                       = 72

hypotenuse = \sqrt{72}

                     = 6\sqrt{2}

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other angles are 90° and 60°

opposite side = d

tan ( 30) = opposite ÷ adjacent

 \frac{1}{\sqrt{3}} = d ÷ 4√3

\frac{1}{\sqrt{3}} = d × (\frac{\sqrt{3}}{4})

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therefore d = \frac{4}{3}

therefore opposite side = \frac{4}{3}

Hypotenuse ² = opposite side ² + adjacent side²

                        =( \frac{4}{3})² +( \frac{4}{\sqrt{3}})²

                        = \frac{64}{9}

therefore hypotenuse = \sqrt{\frac{64}{9}}

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the other two sides are   \frac{4}{3} and                                    \frac{8}{3}

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Answer:

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Step-by-step explanation:

The area (A) of the triangle is calculated as

A = \frac{1}{2} absinC

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A = 0.5 × 12 × 7 × sin49° ≈ 31.7 cm² ( to 1 dec. place )

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