Step-by-step explanation:
For a triangle, any 2 side lengths of the triangle must be greatee than the 3rd side.
Given a triangle with side lengths 11, 23 and x,
we have:
- 11 + 23 > x,
- 11 + x > 23, and
- 23 + x > 11.
Therefore 34 > x and x > 12. => 12 < x < 34.
If we remove the 2. The others will stay the same (roughly might move by 1) EXCEPT the range. Which will drop from 12 to 4
Answer:
cos 2 x=1-sin^2 x
Step-by-step explanation:
x=-135°
cos 2x=cos (-270)=cos (-270+360)=cos 90=0
or cos 2x=1-2sin ²x=1-2(sin (-135))²
=1-2(-sin 135)²
=1-2(sin 135)²
=1-2(sin (180-45))²
=1-2(sin²45)
=1-2 (\frac{1}{\sqrt{2}})²
=1-1
=0
Answer and Step-by-step explanation:
Haven't done this in a while, so here we go:
The rule (I'm not really sure) would have to be negative number and negative number.
This means that:
(4, 0) would become (-4, 0) A'
(6, -2) becomes (-6, 2) B'
(8, -7) becomes (-8, 7) C'
and (0, -5) becomes (0, 5) D'
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