Answer:
The rate at which the distance between them is changing at 2:00 p.m. is approximately 1.92 km/h
Step-by-step explanation:
At noon the location of Lan = 300 km north of Makenna
Lan's direction = South
Lan's speed = 60 km/h
Makenna's direction and speed = West at 75 km/h
The distance Lan has traveled at 2:00 PM = 2 h × 60 km/h = 120 km
The distance north between Lan and Makenna at 2:00 p.m = 300 km - 120 km = 180 km
The distance West Makenna has traveled at 2:00 p.m. = 2 h × 75 km/h = 150 km
Let 's' represent the distance between them, let 'y' represent the Lan's position north of Makenna at 2:00 p.m., and let 'x' represent Makenna's position west from Lan at 2:00 p.m.
By Pythagoras' theorem, we have;
s² = x² + y²
The distance between them at 2:00 p.m. s = √(180² + 150²) = 30·√61
ds²/dt = dx²/dt + dy²/dt
2·s·ds/dt = 2·x·dx/dt + 2·y·dy/dt
2×30·√61 × ds/dt = 2×150×75 + 2×180×(-60) = 900
ds/dt = 900/(2×30·√61) ≈ 1.92
The rate at which the distance between them is changing at 2:00 p.m. ds/dt ≈ 1.92 km/h
Answer:
a or b but i think a
Step-by-step explanation:
Answer:
298
Step-by-step explanation:
given data
total friend = 4
total profit in the first month = 438
two months each friend profit = 184
solution
we consider here total profit second month is = x
so
profit second month = 184 × 4 - 438
x = 736 - 438
x = 298
so that here profit that car wash making the second month is 298
Answer:
$4720
Step-by-step explanation:
Simple Interest
A=P(1+in)
A- Accumulated Amount
P- Principal Amount
i- Interest (÷100)
n- Number Of Years
A=P(1+in)
A=4000(1+0.06×3)
A=4000(1.18)
.°.A=$4720
Answer: BC/BF & M<C
Step-by-step explanation:
