1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
anzhelika [568]
3 years ago
7

Y=2x y=7x + 15 substitution

Mathematics
2 answers:
sergejj [24]3 years ago
7 0

y = 2x \\ y = 7x + 15

Substitute the given value of y into the equation y=7x+15

2x = 7x + 15

Move the variable to the left-hand side and change its sign

2x - 7x = 15

Collect like terms

- 5x = 15

Divide both sides of the equation by -5

x =  - 3

Substitute the given value of x into the equation y=2x

y = 2 \times ( - 3)

Solve the equation for y

y =  - 6

The possible solution of the system is the ordered pair (x,y)

(x,y) = ( - 3, - 6)

hodyreva [135]3 years ago
5 0

Answer:

y = -6 and x = -3

Step-by-step explanation:

 Data :

Eq 1 : y = 2x

Eq 2 : y = 7x + 15

So

  Take eq 1 and solve for x

  ⇒  x = y/2        eq 3

Put eq 3 in eq 2

 y =7 (y/2) +  15

   y - 7y/2 = 15

    ( 2y-7y )/2 = 15

   -5y/2 = 15

  -5y =30

y = -6

And  put value of y in eq 3 to find x

  x = -6/2

  x =-3

You might be interested in
I need help on this.​
SSSSS [86.1K]

Answer:

plot the first point on (0,-4)

from there, rise 2, then run 3

plot another point on (3,-2)

plot another on (6,0), and so on

<em><u>Plz mark as brainliest if correct! Have a nice day!!! </u></em>

<em><u>-Lil G</u></em>

8 0
3 years ago
PLs help 50 PTS!!!!! PLEASE ILL GIVE BRAINLIEST!!!!!
Nookie1986 [14]

Answer:

\large\boxed{y=\dfrac{1}{4}x^2-x-4}

Step-by-step explanation:

The equation of a parabola in vertex form:

y=a(x-h)^2+k

<em>(h, k)</em><em> - vertex</em>

The focus is

\left(h,\ k+\dfrac{1}{4a}\right)

We have the vertex (2, -5) and the focus (2, -4).

Calculate the value of <em>a</em> using k+\dfrac{1}{4a}

<em>k = -5</em>

-5+\dfrac{1}{4a}=-4        <em>add 5 to both sides</em>

\dfrac{1}{4a}=1           <em>multiply both sides by 4</em>

4\!\!\!\!\diagup^1\cdot\dfrac{1}{4\!\!\!\!\diagup_1a}=4

\dfrac{1}{a}=4\to a=\dfrac{1}{4}

Substitute

a=\dfrac{1}{4},\ h=2,\ k=-5

to the vertex form of an equation of a parabola:

y=\dfrac{1}{4}(x-2)^2-5

The standard form:

y=ax^2+bx+c

Convert using

(a-b)^2=a^2-2ab+b^2

y=\dfrac{1}{4}(x^2-2(x)(2)+2^2)-5\\\\y=\dfrac{1}{4}(x^2-4x+4)-5

<em>use the distributive property: a(b+c)=ab+ac</em>

y=\left(\dfrac{1}{4}\right)(x^2)+\left(\dfrac{1}{4}\right)(-4x)+\left(\dfrac{1}{4}\right)(4)-5\\\\y=\dfrac{1}{4}x^2-x+1-5\\\\y=\dfrac{1}{4}x^2-x-4

3 0
3 years ago
5) What is the smallest number by which 1323 must be multiplied so that the product is a perfect
Westkost [7]

Answer:

the smallest number is 7

5 0
3 years ago
A=9 inches, b=12 inches, c=, is the hypotenuse known or unknown?
s2008m [1.1K]
Unknown. C is the hypotenuse, but this problem is solvable.
5 0
3 years ago
Can you help me please
spin [16.1K]
It would be < and > ........


6 0
3 years ago
Read 2 more answers
Other questions:
  • What is half of 6.75
    9·2 answers
  • Which number produces an irrational number when multiplied by -1.25
    15·2 answers
  • What are the common factors of 45,72,and 99
    8·2 answers
  • Which answer describes the type of numbers that are dense? whole numbers and integers whole numbers but not integers rational nu
    11·1 answer
  • Justin started a lawn service business. His rate to maintain an average size lawn is $35. It costs Justin $750 to start the busi
    10·1 answer
  • Which equation can be used to find 150 percent of 500?
    14·2 answers
  • Select the correct answer
    9·1 answer
  • A collection of 30 gems, all of which are identical in appearance, are supposedto be genuine diamonds, but actually contain 8 wo
    6·1 answer
  • Darryl enlarged the size of a rectangle to a
    13·1 answer
  • Solve the system of linear equations by substitution 4x − 2y = 16, 2x + y = 5
    11·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!