Fill in blanks pleasee!

Eliza intends to buy a new vehicle. She wishes to estimate the mean fuel efficiency (in miles per gallon) of all family sized SU

Alik [6]

Answer:

28

Step-by-step explanation:

because if you add all the numbers together you get 433 then you have to divide 433 by the total numbers which is 15 then you get 28.

5 0

3 years ago

Read 2 more answers

Stephanie is trying to figure out the sample size of an experiment. She knows the population SD is 41.5 and the SD of the sample

Bond [772]

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6 0

3 years ago

Which statement is true about the end behavior of the graphed function?

Alik [6]

Answer with explanation:

When you will look at the graph of function, suppose it is denoted by , f(x),

represented by, y=f(x)

$\lim_{x \to \infty} f(x)=+\infty\\\\ \lim_{x \to -\infty} f(x)=+\infty$

At, x=0,the value of f(x)=0.

At, x= -∞, y= +∞

Option A: As the x-values go to positive infinity, the function’s values go to positive infinity.

is true .

5 0

3 years ago

Plot the point (3, 2pi/3), given in polar coordinates, and find other polar coordinates (r, θ )of the point for which the foll

exis [7]

Answer:

(a) $(3, -\frac{4\pi}{3})$

(b) $(-3, \frac{5\pi}{3})$

(c) $(3, \frac{8\pi}{3})$

Step-by-step explanation:

All polar coordinates of point (r, θ ) are

$(r,\theta+2n\pi)$ and $(-r,\theta+(2n+1)\pi)$

where, θ is in radian and n is an integer.

The given point is $(3, \frac{2\pi}{3})$ . So, all polar coordinates of point are

$(3, \frac{2\pi}{3}+2n\pi)$ and $(-3, \frac{2\pi}{3}+(2n+1)\pi)$

(a) $r>0,-2\pi\leq \theta$

Substitute n=-1 in $(3, \frac{2\pi}{3}+2n\pi)$ , to find the point for which $r>0,-2\pi\leq \theta$ .

$(3, \frac{2\pi}{3}+2(-1)\pi)$

$(3, -\frac{4\pi}{3})$

Therefore, the required point is $(3, -\frac{4\pi}{3})$ .

(b) $r$

Substitute n=0 in $(-3, \frac{2\pi}{3}+(2n+1)\pi)$ , to find the point for which $r>0,-2\pi\leq \theta$ .

$(-3, \frac{2\pi}{3}+(2(0)+1)\pi)$

$(-3, \frac{2\pi}{3}+\pi)$

$(-3, \frac{5\pi}{3})$

Therefore, the required point is $(-3, \frac{5\pi}{3})$ .

(c) $r>0,2\pi \leq \theta$

Substitute n=1 in $(3, \frac{2\pi}{3}+2n\pi)$ , to find the point for which $r>0,2\pi \leq \theta$ .

$(3, \frac{2\pi}{3}+2(1)\pi)$

$(3, \frac{2\pi}{3}+2\pi)$

$(3, \frac{8\pi}{3})$

Therefore, the required point is $(3, \frac{8\pi}{3})$ .

4 0

3 years ago

Find the arc that is congruent to arc BF.

stellarik [79]

Answer: choice 2) arc CDE

==================================================

There's a lot going on in this diagram. It might help to use a highlighter or a different pen to mark only what we care about. I marked arc BF in red. The corresponding central angle that goes with arc BF is marked in blue. This is angle BAF. Point A is the center of the circle, so angle BAF is a central angle. We don't know the measure of angle BAF, but we know that it is congruent to angle CAE (marked in green). Why? Because they are vertical angles. Vertical angles are always congruent.

Angle CAE is the central angle that cuts off arc CDE (marked in purple), so we can form this chain of equations:

arc BF = angle BAF
angle BAF = angle CAE
angle CAE = arc CDE

which in short shows
arc BF = arc CDE

note: when I say "arc BF", I mean "minor arc BF" which is the shortest route from B to F. So we go from B to F without going through any other point on the circle.

4 0

4 years ago