Question

On a standardized exam, the scores are normally distributed with a mean of 79 and a standard deviation of 20. Find the z-score of a person who scored 121 on the exam.

Answer 1

Answer:

z = 2.1

Step-by-step explanation:

$z=\frac{x-\mu}{\sigma}\\ \\z=\frac{121-79}{20}\\ \\z=\frac{42}{20}\\ \\z=2.1$

This tells us that the person's score of 121 places them 2.1 standard deviations above the mean score of 79.