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3 years ago

Find the amount that is in the account if $4500 is compounded daily at 3.25% for 6 years

Mathematics

1 answer:

Sindrei [870]3 years ago

6 0

Step-by-step explanation:

1st year interest calculated = 3.25/100 × $4500/1 = $146.25

2nd year principal = 1st year principal + 1st year interest = $4500 + $146.25 = $4646.25. 2nd year interest calculated = 3.25/100 ×$4646.25/1 =$151

3rd year principal = 2nd principal + 2nd year interest = $4646.25 + $151 = $4797.25. 3rd year interest calculated = 3.25/100 × $4797.25/1 = $155.91

4th year principal = 3rd year principal + 3rd year interest =$4797.25 + $155.91 =$4953.16. 4th year principal calculated = 3.25/100 × 4953.16/1 =$160.98

5th year principal = 4th year principal + 4 year interest = &4953.16 +$160.98 = $5114.14. 5th year interest calculated = 3.25/100 × 5114.14/1 =$166.21

6th year principal =5th year principal + 5th year interest = $5114.14 + $166.21 =$5280.35. 6th year interest calculated = 3.25/100 × 5280.35/1 =$171.61

Amount = main principal + compound interest =$4500 +&146.25 +$151+$155.91+$160.98+$166.21+$171.61 =$5451.96

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Andrews [41]

Answer:

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Step-by-step explanation:

This means that ab = 14 and a + b = 15. Simple guess and check reveals (1, 14) or (14, 1).

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3 years ago

Suppose that you were not given the sample mean and sample standard deviation and instead you were given a list of data for the

Troyanec [42]

Answer:

So, the sample mean is 31.3.

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Step-by-step explanation:

We have a list of data for the speeds (in miles per hour) of the 20 vehicles. So, N=20.

We calculate the sample mean :

$\mu=\frac{19 +19 +22 +24 +25 +27 +28+ 37 +35 +30+ 37+ 36+ 39+ 40+ 43+ 30+ 31+ 36+ 33+ 35}{20}\\\\\mu=\frac{626}{20}\\\\\mu=31.3$

So, the sample mean is 31.3.

We use the formula for a sample standard deviation:

$\sigma=\sqrt{\frac{1}{N-1}\sum_{i=1}^{N}(x_i-\mu)^2}$

Now, we calculate the sum

$\sum_{i=1}^{20}(x_i-31.3)^2=(19-31.3)^2+(19-31.3)^2+(22-31.3)^2+(24-31.3)^2+(25-31.3)^2+(27-31.3)^2+(28-31.3)^2+(37-31.3)^2+(35-31.3)^2+(30-31.3)^2+(37-31.3)^2+(36-31.3)^2+(39-31.3)^2+(40-31.3)^2+(43-31.3)^2+(30-31.3)^2+(31-31.3)^2+(36-31.3)^2+(33-31.3)^2+(35-31.3)^2\\\\\sum_{i=1}^{20}(x_i-31.3})^2=926.2\\$

Therefore, we get

$\sigma=\sqrt{\frac{1}{N-1}\sum_{i=1}^{N}(x_i-\mu)^2}\\\\\sigma=\sqrt{\frac{1}{19}\cdot926.2}\\\\\sigma=6.98$

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3 0

3 years ago

Help!!! ---- The graph of a function is a line that passes through the points (1,4), (3,8), and (6,y). What is the value of y?

natima [27]

Answer:

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Step-by-step explanation:

First find the slope of the line. To find the slope of the line, use the slope formula:

$m = \frac{y_2-y_1}{x_2-x_1} = \frac{8-4}{3-1} =\frac{4}{2}=2$

The slope of the line is 2.

Repeat this same process instead with points (1,4) and (6,y). Substitute m = 2.

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Step-by-step explanation:

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