2 years ago

(4k^2– 12) – (6k^2– 3k – 10)

Mathematics

1 answer:

Jet001 [13]2 years ago

5 0

Answer:

-2k^2+3k-2

Step-by-step explanation:

(4k^2– 12) – (6k^2– 3k – 10)

Expanding using distributive prop.

4k^2-12-6k^2+3k+10

-2k^2+3k-2

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KIM [24]

The answer is = 7 11/12

7 0

3 years ago

Read 2 more answers

Select the correct answer.

Jobisdone [24]

Answer:

Step-by-step explanation:

since -6 and -6 are factors of 36 that add up to equal -12, the factored form of the expression is (x-6)^2.

6 0

3 years ago

PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!!

mario62 [17]

Break the numbers under the radical into perfect squares: $\sqrt{2^2*2^2*2*x^2*x^2*z}$ . Take the perfect squares out: you have two 2's, and 2 x's, on the outside of the radical with 2 and z leftover: $3*2*2*x*x*\sqrt{2*z}$ . Multiply everything together to get $12x^2\sqrt{2z}$ .