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Anestetic [448]
2 years ago
7

(4k^2– 12) – (6k^2– 3k – 10)

Mathematics
1 answer:
Jet001 [13]2 years ago
5 0

Answer:

-2k^2+3k-2

Step-by-step explanation:

(4k^2– 12) – (6k^2– 3k – 10)

Expanding using distributive prop.

4k^2-12-6k^2+3k+10

-2k^2+3k-2

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