We have to calculate the value of the car after 3 years at the start of 2017.
= 1200(1-0.30)^{3}
= 12000 × 0.343
= $4,116
Answer:
Step-by-step explanation: see attachment below
Answer:
The probability is 0.9211
Step-by-step explanation:
Let's call K the event that the student know the answer, G the event that the student guess the answer and C the event that the answer is correct.
So, the probability P(K/C) that a student knows the answer to a question, given that she answered it correctly is:
P(K/C)=P(K∩C)/P(C)
Where P(C) = P(K∩C) + P(G∩C)
Then, the probability P(K∩C) that the student know the answer and it is correct is:
P(K∩C) = 0.7
On the other hand, the probability P(G∩C) that the student guess the answer and it is correct is:
P(G∩C) = 0.3*0.2 = 0.06
Because, 0.3 is the probability that the student guess the answer and 0.2 is the probability that the answer is correct given that the student guess the answer.
Therefore, The probability P(C) that the answer is correct is:
P(C) = 0.7 + 0.06 = 0.76
Finally, P(K/C) is:
P(K/C) = 0.7/0.76 = 0.9211
STEP-BY-STEP SOLUTION:
= x^2 - 13x + 30
= x^2 - 10x - 3x + 30
= x ( x - 10 ) - 3 ( x - 10 )
= ( x - 10 ) ( x - 3 )
FINAL ANSWER:
Therefore, the answer is:
C. x - 10
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Answer:
The WIP limit is 0.50 days.
Step-by-step explanation:
The Computation of WIP limits:
to begin with, it is required to compute the process and procedure efficiency which will be computed as follows:
Value Added Time = 12 days (arriving time)
Non-Value-Added Time = 12 days (departure time)
Efficiency = Value Added / (Value Added + Non-Value Added)
= 12 / (12+12)
= 12 / 24
= 0.50 or 50%
the most obligatory throughput time will be 0.25 days to realize the profits
WIP limit = Throughput time / Efficiency
= 0.25 / 50%
= 0.50 days.
The WIP limit is 0.50 days.