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Anton [14]
2 years ago
7

Prove by induction that 7^2n+1 +1 is divisible by 8, for all nEN

Mathematics
1 answer:
fredd [130]2 years ago
7 0

Answer:

See below.

Step-by-step explanation:

Base case:

Replace n with 1.

7^(2×1+1)+1

7^3+1

343+1

344

8 is a factor of 344 since 344=8(43).

Induction hypothesis:

Assume there is some integer n such that 7^(2k+1)+1=8n for positive integer k.

7^(2[k+1]+1)+1

7^(2k+3)+1

7^(2k+1+2)+1

7^(2k+1)7^2+1

49×7^(2k+1)+1

Induction step:

49×(8n-1)+1

49(8n)-49+1

49(8n)-48

8[49n-6]

This means 8 is a factor of 7^(2(k+1)+1)+1.

Thus, this proves for all positive integer n that 8 is a factor of 7^(2n+1)+1.

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Which of the following has a geometric sequence
iren [92.7K]

Answer:

5, -25, 125, -625

Step-by-step explanation:

A geometric sequence is where a number is divided or multiplied by same number continuously

in the third option the number are multiplied by (-5) continuously

8 0
3 years ago
A standard number cube has 6 sides labeled 1 to 6. apu rolls a standard number cube 30 times. How many times can
Leviafan [203]

Answer:

The expected value of rolling a 5 or 6 is 10.

Step-by-step explanation:

The sample space of rolling a standard number cube is:

S = {1, 2, 3, 4, 5 and 6}

The cube is standard, this implies that each side has an equal probability of landing face-up.

So, the probability of all the six outcomes is same, i.e. \frac{1}{6}.

Now it is provided that Apu rolls the cube <em>n</em> = 30 times.

Let the random variable <em>X</em> represent the value on the face of cube.

The event of rolling a 5 and rolling a 6 are mutually exclusive, i.e. they cannot occur together.

So, P (X = 5 and X = 6) = 0.

Compute the probability of getting a 5 or 6 as follows:

P (X = 5 or X = 6) = P (X = 5) + P (X = 6) - P (X = 5 and X = 6)

                            = P (X = 5) + P (X = 6)

                            =\frac{1}{6}+\frac{1}{6}\\\\=\frac{2}{6}\\\\=\frac{1}{3}

Compute the expected value of rolling a 5 or 6 as follows:

E(X = 5\ \text{or}\ X = 6)=n\times P(X = 5\ \text{or}\ X = 6)

                               =30\times \frac{1}{3}\\\\=10

Thus, the expected value of rolling a 5 or 6 is 10.

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Answer:

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Step-by-step explanation:

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B!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

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in my thought 4isthe answer

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