60
45/60 48/60 40/60
LCM 60
Answer:
(2187 *y∧3) / (x∧10 *z) You must know a∧m * a∧n = a∧(m+n) and
a∧m / a∧n = a∧(m-n)
Step-by-step explanation:
First I will rewrite your expression
( 9*x∧(-2)*y∧(-3)*z∧4)∧2 / (3*x∧(-2)*y∧3*z∧(-3))∧(-3) =
= (9∧2) *( (x∧(-2))∧2) * (y∧(-3))∧2 * (z∧4)∧2 / (3∧(-3)) * (x∧(-2)∧(-3)) * ((y∧3)∧(-3)) * (z∧(-3)∧(-3)) =
= ((3∧2)∧2) * (x∧(-4)) * (y∧(-6)) * (z∧8) / (3∧(-3)) * (x∧6) * (y∧(-9)) *(z∧9) =
= (3∧4)/(3∧(-3)) * (x∧(-4-6)) * (y∧(-6-(-9))) * (z∧(8-9) =
= (3∧(4-(-3))) * (x∧(-10)) * (∧y(-6+9)) * (z∧(-1)) = (3∧(4+3) * (x∧(-10)) *(y∧3) * (z∧(-1)) =
(3∧7) * (x∧(-10)) * (y∧3) * (z∧(-1)) = (2187 * y∧3) / (x∧10 * z)
Good luck!!!
The only answer that is true is choice D.
We want to solve
4/7 = x/161
Cross multiply.
7x =(4)(161) = 644
Divide each side by 7.
x = 644/7 = 92
Answer: x = 92
Answer:
Step-by-step explanation:
The given expresion is
For this expression to be factorable using integers, we must find factors of 2c, that will sum up to 3.
We know 2,c are factors of 2c
Their sum should be 3.
This implies that: