(01.01 MC)Which number line shows the solution to 5 + (−5)?

1 answer:

8 0

The answer is the last one, because 5 + (-5) is the same as 5 - 5, which equals 0, which is what the arrow points to in the last one. :)

Hopefully this helps! If you have any more questions or don't understand, feel free to DM me, and I'll get back to you ASAP! :)

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The table shows the temperature (y) at different altitudes (x).

Shtirlitz [24]

Answer/Step-by-step explanation:

2. Using two pairs of values, (0, 59) and (2,000, 51),

$slope (m) = \frac{y_2 - y_1}{x_2 - x_1} = \frac{51 - 59}{2,000 - 0} = \frac{-8}{2,000} = -\frac{1}{250}$

3. The y-intercept is the value of y when x = 0. Thus, x = 0, when y = 59. Therefore,

y-intercept (b) = 59

4. To write an equation in slope-intercept form, simply substitute m = -¹/250, and b = 59, in $y = mx + b$

✅ $y = -\frac{1}{250}x + 59$

5. Substitute x = 5,000 in $y = -\frac{1}{250}x + 59$ .

$y = -\frac{1}{250}(5,000) + 59$

$y = -20 + 59$

$y = 39$

At an altitude of 5,000 ft, temperature would be 39°F

3 0

3 years ago

Graph the line that represents this equation<br> Y=-5x+2

defon

Answer:

i cant answer this in brainly because of lack of display but if you plug in y=5x+2 into mathaway it will show you on a graph

Step-by-step explanation:

5 0

3 years ago

Solve 5x^2 - 7x + 2 = 0 by completing the square.

Reika [66]

Answer: The correct option is (c) $\dfrac{49}{100}.$

Step-by-step explanation: We are given to solve the following quadratic equation by the method of completing the square:

$5x^2-7x+2=0~~~~~~~~~~~~~~~~~~~(i)$

Also, we are to find the constant added on both sides to form the perfect square trinomial.

We have from equation (i) that

$5x^2-7x+2=0\\\\\Rightarrow x^2-\dfrac{7}{5}x+\dfrac{2}{5}=0\\\\\\\Rightarrow x^2-2\times x\times \dfrac{7}{10}+\left(\dfrac{7}{10}\right)^2+\dfrac{2}{5}=\left(\dfrac{7}{10}\right)^2\\\\\\\Rightarrow \left(x-\dfrac{7}{10}\right)^2=\dfrac{49}{100}-\dfrac{2}{5}\\\\\\\Rightarrow \left(x-\dfrac{7}{10}\right)^2=\dfrac{49-40}{100}\\\\\\\Rightarrow \left(x-\dfrac{7}{10}\right)^2=\dfrac{9}{100}\\\\\\\Rightarrow x-\dfrac{7}{10}=\pm\dfrac{3}{10}\\\\\\\Rightarrow x=\pm\dfrac{3}{10}+\dfrac{7}{10}.$

So,

$x=\dfrac{3}{10}+\dfrac{7}{10},~~~~~~~~x=-\dfrac{3}{10}+\dfrac{7}{10}\\\\\\\Rightarrow x=\dfrac{10}{10},~~~~~~~~\Rightarrow x=\dfrac{-3+7}{10}\\\\\\\Rightarrow x=1,~-\dfrac{2}{5}.$