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alexira [117]
2 years ago
7

3.2% of a population are infected with a certain disease. There is a test for the disease, however the test is not completely ac

curate. 91.4% of those who have the disease will test positive. However 4.2% of those who do not have the disease will also test positive (false positives). What is the probability that a person who tests positive actually has the disease? 5) A)0.719 B)0.582 C)0.032 D)0.914 E)0.418
Mathematics
1 answer:
Ivenika [448]2 years ago
6 0
Really don’t kno it’s a hard question
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HELP!!!!
KIM [24]

Answer:

102,000

Step-by-step explanation:

3 0
2 years ago
Blaize is filling a 20,000-gallon swimming pool. If 7040 gallons have already been filled, and the water is entering the pool at
Svetlanka [38]
We can start with subtracting 7040 from 20,000, getting us 12960 gallons remaining, If 720 gallons per hour are coming, we can make the equation 12960 = 720h, with h as hours. Next, we can divide both sides by 720, getting us 18. It will take 18 hours to fill the pool.
3 0
2 years ago
Simplify: 3(4x – 2) + 9 + 2
kirill [66]

Answer:

-6x+5y+8

Step-by-step explanation: subtract 9xfrom 3x

Subtract 2 from 10

-6x+5y+10-2

-6x+5y+8

6 0
3 years ago
Solve for x in the equation:log6-2logx=1.4​
Annette [7]

9514 1404 393

Answer:

  x = (√6)/10^0.7 ≈ 0.488737

Step-by-step explanation:

It can work reasonably well to take antilogs first.

  \log(6)-2\log(x)=1.4\\\\\dfrac{6}{x^2}=10^{1.4}\\\\\dfrac{6}{10^{1.4}}=x^2\\\\x=\dfrac{\sqrt{6}}{10^{0.7}}\approx0.488737

7 0
2 years ago
Which is the value of this expression when p=-2 and q=-1?
saul85 [17]

Answer:

D. 4

Step-by-step explanation:

[(p^2) (q^{-3}) ]^{-2}.[(p)^{-3}(q)^5] ^{-2}\\\\=[(p^2) (q^{-3}) \times(p)^{-3}(q)^5 ]^{-2}\\\\=[(p^{2}) \times(p)^{-3} \times (q^{-3}) \times(q)^5 ]^{-2}\\\\=[(p^{2-3}) \times (q^{5-3}) ]^{-2}\\\\=[(p^{-1}) \times (q^{2}) ]^{-2}\\\\=(p^{-1\times (-2)}) \times (q^{2\times (-2) }) \\\\=p^{2}\times q^{-4} \\\\= \frac{p^2}{q^4}\\\\= \frac{(-2)^2}{(-1)^4}\\\\= \frac{4}{1}\\\\= 4

8 0
3 years ago
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