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MAXImum [283]
4 years ago
14

I can't find the answer, to the question.

Mathematics
1 answer:
lesantik [10]4 years ago
3 0
SSS congruence postulate because two sides are shown to be equal and the third side is shared between both triangles.
You might be interested in
Find the area of the hexagon
IrinaK [193]

Answer:

The area is 78 square inches

Step-by-step explanation:

so you can split the hexagon into two trapezoids, and then find the area of one of those trapezoids, which is what I did. The area of a trapezoid I think is

a, b=base, h=height

A=a+b/2*h

is a really bad way of saying it, but that's how I know to do it.

So anyways I just substituted the numbers with their corresponding letters and solved. So the area of one trapezoid was 39, and since we have two 39's, you do 39*2 and you get 78.

Hope I helped

4 0
3 years ago
Read 2 more answers
Please help, im having trouble cancelling out the numbers and letters! :) thank you
stiv31 [10]
First change the devision to multiplication 
second see the common letters and cross them
8 0
3 years ago
If f(x) = 4x – 5 and g(x) = 3 – 2x, find f(x) + g(x).
lubasha [3.4K]
(4x-5)+(2x-3)

4x+2x= 6x
-5+-3= -8

6x-8
3 0
3 years ago
Solve for m<br> bm + h = 93
vodomira [7]

Answer:

m = 93 - h / b

Step-by-step explanation:

bm + h = 93

bm = 93 - h

m = 93 - h / b

Hope it helps ⚜

3 0
3 years ago
Read 2 more answers
A point $(x, y)$ with integer coordinates is randomly selected such that $0 \le x \le 8$ and $0 \le y \le 4$. what is the probab
ahrayia [7]

Answer:

\frac{1}{3}

Step-by-step explanation:

A point (x, y) with integer coordinates is randomly selected such that 0 \le x \le 8 \:and\: $0 \le y \le 4$.

The possible pairs of (x,y) are:

(0,0),(0,1),(0,2),(0,3),(0,4)

(1,0),(1,1),(1,2),(1,3),(1,4)

(2,0),(2,1),(2,2),(2,3),(2,4)

(3,0),(3,1),(3,2),(3,3),(3,4)

(4,0),(4,1),(4,2),(4,3),(4,4)

(5,0),(5,1),(5,2),(5,3),(5,4)

(6,0),(6,1),(6,2),(6,3),(6,4)

(7,0),(7,1),(7,2),(7,3),(7,4)

(8,0),(8,1),(8,2),(8,3),(8,4)

The Total Possible Outcomes n(S)= 45

The pair (x, y) that satisfies the given condition (say event A: x + y \le 4) are:

(0,0),(0,1),(0,2),(0,3),(0,4)\\(1,0),(1,1),(1,2),(1,3)\\(2,0),(2,1),(2,2)\\(3,0),(3,1)\\(4,0)

n(A)=15

Therefore:

P(A)=\frac{n(A)}{n(S)} =\frac{15}{45} =\frac{1}{3}

5 0
4 years ago
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