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SashulF [63]
4 years ago
8

A point $(x, y)$ with integer coordinates is randomly selected such that $0 \le x \le 8$ and $0 \le y \le 4$. what is the probab

ility that $x + y \le 4$? express your answer as a common fraction.
Mathematics
1 answer:
ahrayia [7]4 years ago
5 0

Answer:

\frac{1}{3}

Step-by-step explanation:

A point (x, y) with integer coordinates is randomly selected such that 0 \le x \le 8 \:and\: $0 \le y \le 4$.

The possible pairs of (x,y) are:

(0,0),(0,1),(0,2),(0,3),(0,4)

(1,0),(1,1),(1,2),(1,3),(1,4)

(2,0),(2,1),(2,2),(2,3),(2,4)

(3,0),(3,1),(3,2),(3,3),(3,4)

(4,0),(4,1),(4,2),(4,3),(4,4)

(5,0),(5,1),(5,2),(5,3),(5,4)

(6,0),(6,1),(6,2),(6,3),(6,4)

(7,0),(7,1),(7,2),(7,3),(7,4)

(8,0),(8,1),(8,2),(8,3),(8,4)

The Total Possible Outcomes n(S)= 45

The pair (x, y) that satisfies the given condition (say event A: x + y \le 4) are:

(0,0),(0,1),(0,2),(0,3),(0,4)\\(1,0),(1,1),(1,2),(1,3)\\(2,0),(2,1),(2,2)\\(3,0),(3,1)\\(4,0)

n(A)=15

Therefore:

P(A)=\frac{n(A)}{n(S)} =\frac{15}{45} =\frac{1}{3}

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6.699rounded to the nearest number
sasho [114]

Answer:

6.700

Step-by-step explanation:

rounded to the hundred would be the same ecen rounded to ten would be the same

7 0
4 years ago
Read 2 more answers
On rainy days, Joe is late to work with probability .3; on nonrainy days, he is late with probability .1. With probability .7, i
Likurg_2 [28]

Answer:

a) 76% probability that Joe is early tomorrow.

b) 64.47% conditional probability that it rained

Step-by-step explanation:

We have these following probabilities:

A 70% probability that it will rain tomorrow.

A 30% probability that it does not rain tomorrow.

If it rains, a 30% probability that Joe is late and a 100-30 = 70% probability that Joe is early.

if it does not rain, a 10% probability that Joe is late and a 100-10 = 90% probability that Joe is early.

(a) Find the probability that Joe is early tomorrow.

Either it rains(70% probability) and he is early(70% probability when it rains), or it does not rain(30% probability) and he is early(90% probability when it does not rain). So

P = 0.7*0.7 + 0.3*0.9 = 0.76

76% probability that Joe is early tomorrow.

(b) Given that Joe was early, what is the conditional probability that it rained?

By the Bayes theorem, this probability is:

The probability that it rained and he was early divided by the probability he was early.

Rained and early

70% probability it rains.

70% probability he is early when it rains.

0.7*0.7 = 0.49

Early

From a), 0.76

Probability

P = \frac{0.49}{0.76} = 0.6447

64.47% conditional probability that it rained

4 0
4 years ago
Hey can you please help me posted picture of question
MAXImum [283]
Answer:
The solutions of the equation are:
4/3 and 5/8

Explanation:
To get the solution of the equation, we can either solve it algebraically or graphically.

1- algebraic solution:
The general form of the quadratic equation is:
ax² + bx + c = 0
The given equation is:
24x² - 47x + 20 = 0
By comparison, we can find that:
a = 24
b = -47
c = 20

Now, to get the roots, we will use the quadratic equation shown in the attached image.

Substituting in the equation, we would find that:
either x = \frac{-(-47) +  \sqrt{(-47)^2-4(24)(20)} }{2(24)} =  \frac{4}{3}
or x = \frac{-(-47) - \sqrt{(-47)^2-4(24)(20)} }{2(24)} = \frac{5}{8}

2- graphical solution:
To get the solution means to get the values of the x-intercepts.
Graphing the function (see attached image), we would find that the solutions are:
0.625 which is equivalent to 5/8 
and 1.3333 which is equivalent to 4/3

Hope this helps :)

3 0
3 years ago
A newspaper reports the following changes in the temperature of a city over 4 days:
suter [353]

Answer:Consider the parent equation of a every quadratic equation which is y=^2. which of the following points below meets the requirement by falling in the solution set? y≤x^2 a; y=10,000 b; y=-1.000 c; y=0,5 d; y=17/3

Step-by-step explanation:

8 0
3 years ago
Please Help Me with this Question. I do not understand it.
ludmilkaskok [199]

Answer: 30

Step-by-step explanation:

the formula for the area of a triangle is base times height divided by 2

A=bh/2

the base in this triangle is 15 and the height is 4

(15)(4)/2

60/2

30

7 0
3 years ago
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