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KiRa [710]
2 years ago
5

Calculate: f(4) - (g(2) + f(3)) = h(1) + f(1) x g(3) =

Mathematics
2 answers:
Tems11 [23]2 years ago
4 0

Answer:

1)  f-2g

2) h+3fg

Step-by-step explanation:

1)

  • f(4) - g(2) + f(3))
  • 4f - 2g + 3f
  • 4f - 3f - 2g
  • f - 2g

2)

  • h(1) + f(1) x g(3)
  • h + f x 3g
  • h + 3fg
Natasha2012 [34]2 years ago
4 0

#1.

f(4) - g(2) + f(3))

4f-2g + 3f

4f - 3f - 2g

f-2g

#2.

h(1) + f(1) x g(3)

h+fx 3g

h + 3fg

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-1.5

Step-by-step explanation:

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g In R simulate a sample of size 20 from a normal distribution with mean µ = 50 and standard deviation σ = 6. Hint: Use rnorm(20
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Answer:

> a<-rnorm(20,50,6)

> a

[1] 51.72213 53.09989 59.89221 32.44023 47.59386 33.59892 47.26718 55.61510 47.95505 48.19296 54.46905

[12] 45.78072 57.30045 57.91624 50.83297 52.61790 62.07713 53.75661 49.34651 53.01501

Then we can find the mean and the standard deviation with the following formulas:

> mean(a)

[1] 50.72451

> sqrt(var(a))

[1] 7.470221

Step-by-step explanation:

For this case first we need to create the sample of size 20 for the following distribution:

X\sim N(\mu = 50, \sigma =6)

And we can use the following code: rnorm(20,50,6) and we got this output:

> a<-rnorm(20,50,6)

> a

[1] 51.72213 53.09989 59.89221 32.44023 47.59386 33.59892 47.26718 55.61510 47.95505 48.19296 54.46905

[12] 45.78072 57.30045 57.91624 50.83297 52.61790 62.07713 53.75661 49.34651 53.01501

Then we can find the mean and the standard deviation with the following formulas:

> mean(a)

[1] 50.72451

> sqrt(var(a))

[1] 7.470221

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