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rusak2 [61]
3 years ago
13

(52) Pleaase check ym answer

Mathematics
1 answer:
Alinara [238K]3 years ago
4 0
X = measure of each of the legs
"perimeter is 8 more than 2 times one of the legs" ---> P = 2x+8
P = 28 is the given perimeter

So,
P = 2x+8
28 = 2x+8
2x+8 = 28
2x = 20
x = 10

If x = 10, then the two legs add up to x+x = 10+10 = 20
Leaving P-20 = 28-20 = 8 inches left over for the base

You have the correct answer (choice D, 8 inches) though your steps are a bit confusing at some parts. Such as the part where you wrote 2x = 10 twice. I think I know what you were trying to say. 

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See explanation

Step-by-step explanation:

In triangles AKU and AVP,

  1. Angles AKU and AVP are congruent as inscribed angles subtended on the same arc PU
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By AA similarity theorem, ΔAKU and ΔAVP are similar.  

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Triss [41]

Keller collected $62.48 and Izzy collected $47.83 and J collected $19.98

Step-by-step explanation:

Step 1; Assume that J collected $x, Keller collected $y and Izzy collected $z. All three combined collected $125.95, so

x + y + z = 125.95, take this as equation 1.

From the given data, the following equations can be formed.

y = 42.50 + x or x = y - 42.50 take this as equation 2 and

y = 15 + z, take this as equation 3.

Step 2; Now we must determine x and y in terms of z, so that equation 1 can be solved (the equations can be in terms of any term x, y or z.)

Rearranging equation 2 and 3,

we get 15 + z so  x = y - 42.50, y = x = 15 + z - 42.50, take this as equation 4,

If we substitute equations 4, 2 in 1, we get

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Substitute z = 47.833 in equation 3.

y = 15 + 47.8333 = 62.4833.

Substitute y = 62.4833 in equation 2,

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11111nata11111 [884]

Answer:

\sqrt{8}----- 2units,2units

\sqrt{7} ------\sqrt{5}units,\sqrt{2}units

\sqrt{5}-------1unit,2units

3------2units, \sqrt{5}units

Step-by-step explanation:

Use pythagorean's theorem to solve each pair individually.

The instructions say that you have the two sides (a and b) and you have to match it with their hypothenuse.

Formula: c^2=a^2+b^2

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Plug this into the formula.

c=\sqrt{(\sqrt{5} )^2+(\sqrt{2})^2 }

The square here eliminates the roots.

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2. a=\sqrt{3}, b=4

c=\sqrt{(\sqrt{3} )^2+(4)^2}\\ c=\sqrt{3+16}\\ c=\sqrt{19}

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5. a=1, b=2

c=\sqrt{(1)^2+(2)^2}\\ c=\sqrt{1+4}\\ c=\sqrt{5}

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