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Ket [755]
3 years ago
14

HELPWW!

Mathematics
1 answer:
yan [13]3 years ago
5 0
The answer is A. The line would run through the point (-6,8) and run parallel to the x -axis, tangent to the circle.

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Help me solve this please ❤<br>I will give the right answer brainliest <br>​
luda_lava [24]

Step-by-step explanation:

√((1 + sin x) / (1 − sin x)) + √((1 − sin x) / (1 + sin x))

Square and take the square root.

√[√((1 + sin x) / (1 − sin x)) + √((1 − sin x) / (1 + sin x))]²

√[(1 + sin x) / (1 − sin x) + 2 + (1 − sin x) / (1 + sin x)]

Add the fractions using least common denominator.

√[((1 + sin x)² + (1 − sin x)²) / (1 − sin²x) + 2]

√[(1 + 2 sin x + sin²x + 1 − 2 sin x + sin²x) / (1 − sin²x) + 2]

√[(2 + 2 sin²x) / (1 − sin²x) + 2]

Use Pythagorean identity:

√[(2 + 2 sin²x) / (cos²x) + 2]

√[2 sec²x + 2 tan²x + 2]

√[2 sec²x + 2 (tan²x + 1)]

Use Pythagorean identity:

√[2 sec²x + 2 sec²x]

√[4 sec²x]

±2 sec x

If x is in the second quadrant, then sec x < 0.

-2 sec x

6 0
4 years ago
The school bookstore ordered three-ring notebooks. They put 75% of the order in the warehouse and sold 0% of the rest in the fir
vladimir2022 [97]

Answer:

Step-by-step explanation:

100% divided by 4 is 25%

25 books were 1/4 of the books total.

the other 3/4 would be 75%

they og ordered 100 books

7 0
3 years ago
Can someone help me fill this out
Gwar [14]

Answer:

Step-by-step explanation:

4 0
3 years ago
Find the 72nd term of the arithmetic sequence -27, -11, 5,
mixas84 [53]

Answer:

1109

Step-by-step explanation:

an = d (n - 1) + c

an = what you're looking for

n = term position

d = the common difference, in your case, 16

c = first term of the sequence, or -27

a₇₂ = 16(72 - 1) + -27 = 1109

5 0
3 years ago
Find the linear approximation of the function g(x) = 3 root 1 + x at a = 0. g(x). Use it to approximate the numbers 3 root 0.95
Virty [35]

Answer:

L(x)=1+\dfrac{1}{3}x

\sqrt[3]{0.95} \approx 0.9833

\sqrt[3]{1.1} \approx 1.0333

Step-by-step explanation:

Given the function: g(x)=\sqrt[3]{1+x}

We are to determine the linear approximation of the function g(x) at a = 0.

Linear Approximating Polynomial,L(x)=f(a)+f'(a)(x-a)

a=0

g(0)=\sqrt[3]{1+0}=1

g'(x)=\frac{1}{3}(1+x)^{-2/3} \\g'(0)=\frac{1}{3}(1+0)^{-2/3}=\frac{1}{3}

Therefore:

L(x)=1+\frac{1}{3}(x-0)\\\\$The linear approximating polynomial of g(x) is:$\\\\L(x)=1+\dfrac{1}{3}x

(b)\sqrt[3]{0.95}= \sqrt[3]{1-0.05}

When x = - 0.05

L(-0.05)=1+\dfrac{1}{3}(-0.05)=0.9833

\sqrt[3]{0.95} \approx 0.9833

(c)

(b)\sqrt[3]{1.1}= \sqrt[3]{1+0.1}

When x = 0.1

L(1.1)=1+\dfrac{1}{3}(0.1)=1.0333

\sqrt[3]{1.1} \approx 1.0333

7 0
3 years ago
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