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Free_Kalibri [48]
2 years ago
12

(25 points) Ricardo wants to mix 1 part yellow paint to 3 parts blue paint to make a certain shade

Mathematics
1 answer:
Lapatulllka [165]2 years ago
6 0

Answer:

6 pints of blue

Step-by-step explanation:

note- 8 pints = 1 gallon

Original ratio- 3 parts blue to 1 part yellow ( 3b:1y)

This will make 4 pints if we say that 1 part can be one pint
Ricardo needs 8 pints

Divide the amount needed by how much one portion will make

8/4= 2

Multiply original ratio by 2 to see how many pints of each he’ll need for his new amounts

1y*2= 2 pints yellow paint

3b*2=6 pints of blue paint

So to make 8 pints of green with 3 parts blue to 1 part yellow Ricardo will need 6 pints of blue paint


Let me know if you have any questions and I hope this helps! :)

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katovenus [111]

Hello from MrBillDoesMath!

Answer:

Discussion:

I stared at the numbers 19, 29, 39, 49, 59, 69,... for a second and noticed that adding 10 to any number gives the next number to the right. For example,


19 + 10 = 29

29 + 10 = 39

39 + 10 = 49

etc.....


A recursive formula would be:

a(0) = 19        

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Regards,  

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If you break up the number under the radical in √36 into two factors that are perfect squares, what are the two factors?
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Step-by-step explanation:


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A circle is circumscribed around a square and another circle is inscribed in the square. If the area of the square is 9 in2, wha
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Answer:

√2:1

Step-by-step explanation:

First we need to know that the length of the side of the square is equal to the diameter of the inscribed circle i.e

L = di

Given the area of the square to be 9in², we can get the length of the square.

Area of a square = L²

L is the length of the square.

9 = L²

L = √9

L = 3in

Hence the length of one side of the square is 3in

This means that the diameter of the inscribed circle di is also 3in.

Circumference of a circle = π×diameter of the circle(di)

Circumference of inscribed circle = π×3

= 3π in

For the circumscribed circumscribed circle, diameter of the outer circle will be equivalent to the diagonal of the square.

To get the diagonal d0, we will apply the Pythagoras theorem.

d0² = L²+L²

d0² = 3²+3²

d0² = 9+9

d0² = 18

d0 = √18

d0 = √9×√2

d0 = 3√2 in

Hence the diameter of the circumscribed circle (d0) is 3√2 in

Circumference of the circumscribed circle = πd0

= π(3√2)

= 3√2 π in

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