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Free_Kalibri [48]
2 years ago
12

(25 points) Ricardo wants to mix 1 part yellow paint to 3 parts blue paint to make a certain shade

Mathematics
1 answer:
Lapatulllka [165]2 years ago
6 0

Answer:

6 pints of blue

Step-by-step explanation:

note- 8 pints = 1 gallon

Original ratio- 3 parts blue to 1 part yellow ( 3b:1y)

This will make 4 pints if we say that 1 part can be one pint
Ricardo needs 8 pints

Divide the amount needed by how much one portion will make

8/4= 2

Multiply original ratio by 2 to see how many pints of each he’ll need for his new amounts

1y*2= 2 pints yellow paint

3b*2=6 pints of blue paint

So to make 8 pints of green with 3 parts blue to 1 part yellow Ricardo will need 6 pints of blue paint


Let me know if you have any questions and I hope this helps! :)

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Write as a single power of 6<br> (6^5)^4
babunello [35]

Answer:

6^20

Step-by-step explanation:

When two indices are in brackets, you just have to multiply them.

3 0
3 years ago
Find the value of the variable.
nalin [4]

Answer:

The variable, y is 11°

Step-by-step explanation:

The given parameters are;

in triangle ΔABC;          {}              in triangle ΔFGH;

Segment \overline {AB} = 14         {}               Segment \overline {FG} = 14

Segment \overline {BC} = 27         {}              Segment \overline {GH} = 19

Segment \overline {AC} = 19         {}               Segment \overline {FH} = 2·y + 5

∡A = 32°                       {}                ∡G = 32°

∡A = ∠BAC which is the angle formed by segments \overline {AB} = 14 and \overline {AC} = 19

Therefore, segment \overline {BC} = 27, is the segment opposite to ∡A = 32°

Similarly, ∡G = ∠FGH which is the angle formed by segments \overline {FG} = 14 and \overline {GH} = 19

Therefore, segment \overline {FH} = 2·y + 5, is the segment opposite to ∡A = 32° and triangle ΔABC ≅ ΔFGH by Side-Angle-Side congruency rule which gives;

\overline {FH} ≅ \overline {BC} by Congruent Parts of Congruent Triangles are Congruent (CPCTC)

∴ \overline {FH} = \overline {BC} = 27° y definition of congruency

\overline {FH} = 2·y + 5 = 27° by transitive property

∴ 2·y + 5 = 27°

2·y = 27° - 5° = 22°

y = 22°/2 = 11°

The variable, y = 11°

8 0
2 years ago
Pls help immediately
STatiana [176]

Answer:

(3,2)

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
A) Find the distance of line segment PR. Round answer to the nearest tenth. B) Find the distance around the park (perimeter).
juin [17]

Answer:

A. PR = 80.6 yd

B. Perimeter = 190.6 yd

Step-by-step explanation:

A. Distance between P(10, 50) and R(80, 10):

PR = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}

PR = \sqrt{(80 - 10)^2 + (10 - 50)^2}

PR = \sqrt{(70)^2 + (-40)^2}

PR = \sqrt{4,900 + 1,600}

PR = \sqrt{6,500}

PR = 80.6 yd (nearest tenth)

B. Distance around the park = Perimeter = PR + PQ + QR

PR = 80.6 yd

PQ = |50 - 10| = 40 yd

QR = |80 - 10| = 70 yd

Perimeter = 80.6 + 40 + 70

Perimeter = 190.6 yd

7 0
2 years ago
<img src="https://tex.z-dn.net/?f=%20%5Ctan%28x%20%29%20%20%3D%20%20%5Cfrac%7B10%7D%7B60%7D%20" id="TexFormula1" title=" \tan(x
chubhunter [2.5K]

tan(x) = 10/60

tan(x) = 1/6

tan(x) = a -> x = arctan(a) + πn

x = arctan(1/6) + πn

x = 0.165 + πn

Best of Luck!

7 0
3 years ago
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