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stiks02 [169]
2 years ago
11

Find the vertex of the parabola. y = negative 4 x squared + 24 x minus 35 a. ( -3, 1) c. ( 3, 1) b. ( -3, -1) d. ( -1, -3)

Mathematics
1 answer:
Alex_Xolod [135]2 years ago
3 0

Answer:

(3, 1)

Step-by-step explanation:

y = -4x² + 24x - 35

Find the vertex by using the formula:

  • (h, k) → \displaystyle \Big [ -\frac{b}{2a}, \ f \Big (-\frac{b}{2a} \Big ) \Big ]

In this problem, we have:

  • a = -4
  • b = 24
  • c = -35

Using 24 for b and -4 for a, we can substitute these values into the vertex formula:

  • \displaystyle -\frac{b}{2a} \rightarrow -\frac{24}{2(-4)} = \frac{-24}{-8} = 3

The h-value for the vertex is 3.

Now let's plug 3 back into the standard form equation to solve for the k-value of the vertex.

  • -4x^2 + 24x - 35 \rightarrow -4(3)^2+24(3)-35 = -36 + 72 - 35  =  1

The k-value for the vertex is 1.

The vertex of the parabola is (3, 1).

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kirza4 [7]

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Step-by-step explanation:

Given the following data;

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a. To find the simple interest;

S.I = (PRT)/100

S.I = (1000*2.9*6)/100

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b. To find the compound interest;

A = P(1 + \frac{r}{100})^{t}

Substituting into the formula, we have;

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A = 1000(1.029)^{6}

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Answer:

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Step-by-step explanation:

Pull out like factors :

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Solve :    -3   =  0

This equation has no solution.

A a non-zero constant never equals zero.

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Burka [1]

Answer:

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Step-by-step explanation:

Given

f(x) = \frac{3}{x+2} - \sqrt{x-3}

Evaluate f(19) by substituting x = 19 into f(x)

f(19) = \frac{3}{19+2} - \sqrt{19-3}

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