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yarga [219]
2 years ago
8

If you can solve this then you get the brainliest!

Mathematics
2 answers:
Law Incorporation [45]2 years ago
7 0

Answer:

x in top middle row.

x in middle left row.

x in middle right row.

x in last down middle row.

please

Alika [10]2 years ago
4 0

Start with a blank grid

\begin{array}{c|c|c} &  & \\\cline{1-3} &  & \\\cline{1-3} &  & \end{array}

Place 3 x's to clump into one corner like this

\begin{array}{c|c|c}x & x & \\\cline{1-3} x&  & \\\cline{1-3}&  & \end{array}

Then fill out the opposite corner in a similar fashion to make sure that we don't get 3 in a row/column/diagonal anywhere

\begin{array}{c|c|c}x & x & \\\cline{1-3}x &  & x\\\cline{1-3} & x & x\end{array}

Each row has exactly 2 x's and each column has exactly 2 x's. The main diagonal has 2 x's, while the off diagonal has no x's at all.

I'm not sure if this is the only configuration where this is possible (if we ignored any rotated versions of what is shown above).

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Simplify and evaluate<br><br> (6)(2^3)^2 / (2^2)^2
sveticcg [70]

Simplify and evaluate

(6)(2^3)^2 = 384

(2^2)^2 = 16

5 0
2 years ago
Just please help i need help please!!
anastassius [24]

Answer: 1- a square has 4 equal sides so if one side is 9cm then the rest are 9cm, so 9x4= 36cm

2- do the same thing as part 1 but add a power of 2 to it, so 36^2 = 1296cm

Step-by-step explanation:

5 0
2 years ago
Jade uses $30 from her checking account to donate money to her favorite charity. Will this be a deposit or a
Ghella [55]

Answer:

deposit

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
Giá trị x thoả mãn x(x − 3) + x − 3 =0 là
svet-max [94.6K]

Here we will use the trial and error method.

  • We will try putting different values of x.
<h3 /><h3>1st of all</h3><h3>x=1</h3>

\begin{gathered}\\ \sf\longmapsto 1(1-3)+1-3=0\end{gathered}

\begin{gathered}\\ \sf\longmapsto (-2)+1-3=0\end{gathered}

\begin{gathered}\\ \sf\longmapsto -2+1-3=0\end{gathered}

\begin{gathered}\\ \sf\longmapsto -2-2=0\end{gathered}

\begin{gathered}\\ \sf\longmapsto -4≠0\end{gathered}

<h2>Now,</h2><h3>x=2</h3>

\begin{gathered}\\ \sf\longmapsto 2(2-3)+2-3=0\end{gathered}

\begin{gathered}\\ \sf\longmapsto 2(-1)+2-3=0\end{gathered}

\begin{gathered}\\ \sf\longmapsto -2+2-3=0\end{gathered}

\begin{gathered}\\ \sf\longmapsto -3≠0\end{gathered}

<h2>Again,</h2><h3>x=3</h3>

\begin{gathered}\\ \sf\longmapsto 3(3-3)+3-3=0\end{gathered}

\begin{gathered}\\ \sf\longmapsto 3(3-3)=0\end{gathered}

\begin{gathered}\\ \sf\longmapsto 3×0=0\end{gathered}

\begin{gathered}\\ \sf\longmapsto 0=0\end{gathered}

<h3>☣Hence, The value of X as 3 satisfies the equation!</h3>
5 0
2 years ago
Help, guys I have NO CLUE how to do this
Nikitich [7]
Subtract c and then x = y - c

And that's it!
3 0
3 years ago
Read 2 more answers
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