Question

Find the equation (in terms of x ) of the line through the points (-4,-4) and (2,4)

Answer 1

Answer:

$y=\frac{4}{3}x+\frac{4}{3}$

Step-by-step explanation:

Let $(x_1,y_1)\rightarrow(-4,-4)$ and $(x_2,y_2)\rightarow(2,4)$:

Determine slope

$m=\frac{y_2-y_1}{x_2-x_1}\\ \\m=\frac{4-(-4)}{2-(-4)}\\ \\m=\frac{4+4}{2+4}\\ \\m=\frac{8}{6}\\ \\m=\frac{4}{3}$

Use either coordinate point to find "b", the y-intercept

$y=mx+b\\\\4=\frac{4}{3}(2)+b\\ \\4=\frac{8}{3}+b\\ \\\frac{4}{3}=b$

Final Equation

$y=\frac{4}{3}x+\frac{4}{3}$