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maria [59]
2 years ago
6

MARKING AS BRAINLIEST! LAST ATTEMPT! ) show ur work

Mathematics
1 answer:
Ivenika [448]2 years ago
5 0

- 3 \sqrt{180 {x}^{5}y }  =  - 3 \sqrt{36 {x}^{4} \times 5xy }  =  - 18  {x}^{2} \sqrt{5xy}

5 \sqrt{108xy {z}^{2} }  = 5 \sqrt{36 {z}^{2} \times 3xy }  = 30z \sqrt{3xy}

3x \sqrt{x {y}^{10} {z}^{7}  }  = 3x \sqrt{ {y}^{10} {z}^{6}  \times xz }  = 3x {y}^{5}  {z}^{3}  \sqrt{xz}

\sqrt{ {x}^{3} }  =  \sqrt{ {x}^{2} \times x }  = x \sqrt{x}

\sqrt{x {y}^{3}z }  = y \sqrt{xyz}

\sqrt{18 {x}^{2}y }  =  \sqrt{9 {x}^{2} \times 2y }  = 3x \sqrt{2y}

\sqrt{32 {x}^{4}  {y}^{2} }  =  \sqrt{16 ({ {x}^{2} })^{2} {y}^{2}  \times 2 }  =  4 {x}^{2} y \sqrt{2}

2 \sqrt{16 {x}^{7} {y}^{3} {z}^{4}   }  = 2 \sqrt{ {4}^{2} {x}^{6} {y}^{2} ( { {z}^{2} )}^{2}  \times xy  }    = 8 {x}^{3} y {z}^{2}  \sqrt{xy}

{x}^{2}  \sqrt{ {x}^{3} {y}^{2}  }  =  {x}^{2}  \sqrt{ {x}^{2} {y}^{2}  \times x }  =  {x}^{3} y \sqrt{x}

Answer: ......

Ok done. Thank to me :>

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your largest exponent is 54i^2, so that's first in out equation, next 27i, and 24i (you can combine these because they are like term) which equals 51i, after that you just add the 12 on the end, so the final equation looks like this:

54i^2+51i+12


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