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maria [59]
2 years ago
6

MARKING AS BRAINLIEST! LAST ATTEMPT! ) show ur work

Mathematics
1 answer:
Ivenika [448]2 years ago
5 0

- 3 \sqrt{180 {x}^{5}y }  =  - 3 \sqrt{36 {x}^{4} \times 5xy }  =  - 18  {x}^{2} \sqrt{5xy}

5 \sqrt{108xy {z}^{2} }  = 5 \sqrt{36 {z}^{2} \times 3xy }  = 30z \sqrt{3xy}

3x \sqrt{x {y}^{10} {z}^{7}  }  = 3x \sqrt{ {y}^{10} {z}^{6}  \times xz }  = 3x {y}^{5}  {z}^{3}  \sqrt{xz}

\sqrt{ {x}^{3} }  =  \sqrt{ {x}^{2} \times x }  = x \sqrt{x}

\sqrt{x {y}^{3}z }  = y \sqrt{xyz}

\sqrt{18 {x}^{2}y }  =  \sqrt{9 {x}^{2} \times 2y }  = 3x \sqrt{2y}

\sqrt{32 {x}^{4}  {y}^{2} }  =  \sqrt{16 ({ {x}^{2} })^{2} {y}^{2}  \times 2 }  =  4 {x}^{2} y \sqrt{2}

2 \sqrt{16 {x}^{7} {y}^{3} {z}^{4}   }  = 2 \sqrt{ {4}^{2} {x}^{6} {y}^{2} ( { {z}^{2} )}^{2}  \times xy  }    = 8 {x}^{3} y {z}^{2}  \sqrt{xy}

{x}^{2}  \sqrt{ {x}^{3} {y}^{2}  }  =  {x}^{2}  \sqrt{ {x}^{2} {y}^{2}  \times x }  =  {x}^{3} y \sqrt{x}

Answer: ......

Ok done. Thank to me :>

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The correct answer is 5/7 and 5/4.

We have given that the expression

a. \frac{2}{7}+\frac{3}{7}

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<h3>What is the dividando and componendo?</h3>

Components and dividend is a theorem on proportions that allows for a quick way to perform calculations and reduce the number of expansions needed. It is particularly useful when dealing with equations involving fractions or rational functions in mathematical Olympiads, especially when you see fractions.

We have to determine the value of the given expression,

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b. 2\times \frac{1}{4} +\frac{3}{4}\\=\frac{2}{4} +\frac{3}{4}\\=\frac{5}{4}

Therefore the correct answer is 5/7 and 5/4.

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brainly.com/question/723406

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