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3 years ago

Find the equation of the line perpendicularly to y=3x - 6 that runs through the point (-1, -3), need help ASAP

Mathematics

1 answer:

mr_godi [17]3 years ago

3 0

Answer:

y = 1/3x - 10/3

Step-by-step explanation:

Perpendicular lines have slopes that are negative reciprocals of one another so m = -1/3

Given (-1,-3)

y = mx + b

-3 = -1/3(-1) + b

-9/3 = 1/3 + b

b = -10/3

so y = 1/3x - 10/3

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Solve for indicated side. Round to the nearest hundredth. Z=

Diano4ka-milaya [45]

Answer:

z ≈ 145.62

Step-by-step explanation:

using the sine ratio in the right triangle

sin18° = $\frac{opposite}{hypotenuse}$ = $\frac{45}{z}$ ( multiply both sides by z )

z × sin18° = 45 ( divide both sides by sin18° )

z = $\frac{45}{sin18}$ ≈ 145.62 ( to the nearest hundredth )

6 0

2 years ago

Please help me with this

postnew [5]

Answer:

(-1, 2/3).

Step-by-step explanation:

Taking the derivative of f, we get f' = x^2 - 1 = 0. Thus, x = -1 and x = +1.

At the relative max, y = (1/3)(-1)^3 - (-1) = -1/3 + 1 = 2/3.

The relative maximum is at (-1, 2/3).

3 0

3 years ago

4= Sx+10/2 that’s a fraction btw

frozen [14]

Answer:

4= Sx+10/2 simplifies to -s*x-1=0

Step-by-step explanation:

8 0

3 years ago

HELP PLS

aleksandrvk [35]

So this is a lot of work but ghe answers are (fix)

4 0

3 years ago

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Please help me with this also good morning!

Doss [256]

Answer:

Divide both sides by 6 :)

8 0

3 years ago

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