Answer:

And replacing we got:

So we are going to expect about 2,85 automobiles for this case.
Step-by-step explanation:
For this case we define the random variable X as "number of automobiles lined up at a Lakeside Olds dealer at opening time (7:30 a.m.)" and we know the distribution for X is given by:
X 1 2 3 4
P(X) 0.05 0.30 0.40 0.25
The expected value of a random variable X is the n-th moment about zero of a probability density function f(x) if X is continuous, or the weighted average for a discrete probability distribution, if X is discrete
For this case we can calculate the epected value with this formula:

And replacing we got:

So we are going to expect about 2,85 automobiles for this case.
I think it's 25%
Hope that helps
Answer:

Step-by-step explanation:
f(x)+g(x)

combine like terms --

Answer:
80
Step-by-step explanation:
We let x be Ann's savings.
Betty saves 3 times as much as Ann.
This implies that Betty's savings in terms of x

Charles save 390 less than Ann.
This implies Charles savings

Betty saves 1330 more than Charles.
This implies that when we deduct Charles savings from Betty's we have to get 1330.
Mathematical equation for the problem:

Expand :


Subtract 390 from both sides.


Divide through by 2


Hence Charles saving is

Answer: C 20
Explanation: Plug in 2 for k.
2^2 - (2-10) + 4(2) = 20