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solong [7]
3 years ago
5

Find the area of this parallelogram please help

Mathematics
1 answer:
prohojiy [21]3 years ago
3 0

Answer:

A=168ft

Step-by-step explanation:

Area = base * hight

Area = 12 * 14

Area = 168 ft

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In a game called taxation and evasion, a player rolls a pair of dice. if on any turn the sum is 7, 11, or 12, the player gets au
bezimeni [28]

The probability that she gets audited no more than 2 times is 0.896482...

As, a pair of dice are rolling here, so the number of total possible outcome = (6×6) = 36

For Sum = 7 , the favorable outcomes are: (1,6) (2,5) (3,4) (4,3) (5,2) and (6,1)

For Sum = 11 , the favorable outcomes are: (5,6) and (6,5)

For Sum = 12 , the favorable outcome is: (6,6)

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So, P(7)= \frac{6}{36} =\frac{1}{6}

P(11) = \frac{2}{36} = \frac{1}{18}

P(12) = \frac{1}{36}

P( 7 or 11 or 12) = \frac{1}{6}+\frac{1}{18}+\frac{1}{36} = \frac{6+2+1}{36}=\frac{9}{36} = \frac{1}{4}

Here the total number of trials = 5 and the probability of getting audited = \frac{1}{4}

According the binomial distribution formula:

P(X) = (ⁿCₓ )(P)ˣ (1-P)ⁿ⁻ˣ

where P(X) is the probability of x successes out of n trials

Here, n= 5 and P = 1/4 and we need to find the probability of getting audited no more than 2 times. This means she can gets audited 0, 1 or 2 times.

So,

P(X=0)+P(X=1) +P(X=2)\\\\= [^5C^0 (\frac{1}{4})^0 (1-\frac{1}{4})^5^-^0 ]+[^5C^1 (\frac{1}{4})^1 (\frac{3}{4})^5^-^1]+[^5C^2 (\frac{1}{4})^2 (\frac{3}{4})^5^-^2]\\\\=  (\frac{3}{4})^5+ (5) (\frac{1}{4}) (\frac{3}{4})^4  +(10)(\frac{1}{4})^2 (\frac{3}{4})^3\\\\=0.237304... +0.395507...+0.263671...\\\\ = 0.896482...

So, the probability that she gets audited no more than 2 times is 0.896482...

5 0
3 years ago
What is the interquartile range of the data shown in the box plot???<br> HELP
Artyom0805 [142]

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Step-by-step explanation:

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At an electronics store, a $165 television is marked up 110%. Trevor purchases the TV and must pay 6.5% sales tax.
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I believe the correct answer is c

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Two cyclists, Alan and Brian, are racing around oval track of length 450m on the same direction simultaneously from the same poi
skelet666 [1.2K]

Answer:

Alan: 200 m/min

Brian: 150 m/min

Step-by-step explanation:    

Given : Two cyclists, Alan and Brian, are racing around oval track of length 450m on the same direction simultaneously from the same point. Alan races around the track in 45 seconds before Brian does and overtakes him every 9 minutes.

To find : What are their rates, in meters per minute?

Solution :

Let n represent the number of laps that Alan completes in 9 minutes.

Then n-1 is the number of laps Brian completes.

45 seconds = 3/4 minutes.

The difference in their lap times in minutes per lap is

\frac{9}{(n -1)}-\frac{9}{n} =\frac{3}{4}

Solving the equation we get,

\frac{9n-9n+9}{n(n -1)} =\frac{3}{4}

9\times 4=3\times n(n -1)

36=3\times n(n -1)

n^2-n-12=0

n^2-4n+3n-12=0

n(n-4)+3(n-4)=0

(n-4)(n+3)=0

n=4,-3

Neglecting n=-3

So, n=4

Then Alan's speed in m/min is

S=\frac{D}{T}

S_a=\frac{4\times 450}{9}

S_a=200 m/min

Brian completes 3 laps in that 9-minute time, so his rate is

S_b=\frac{3\times 450}{9}

S_b=150 m/min

Therefore, Alan: 200 m/min

Brian: 150 m/min

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