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2 years ago

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Mathematics

1 answer:

Lubov Fominskaja [6]2 years ago

6 0

???????what that guy said

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What is the y-intercept of the graph of the equation y=4(3^x)?

eimsori [14]

Answer:

The y-intercept is (0, 4).

Step-by-step explanation:

At the y-intercept x = 0 so

y = 4(3^0)

y = 4*1 = 4.

So the y-intercept is (0, 4).

8 0

2 years ago

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Adele has 3 64-ounce cartons of orange juice and 3 48-ounce cans of apple juice. How much juice does she have altogether?

Readme [11.4K]

She has 6 ounce of cans

7 0

3 years ago

How to simplify this expression

dexar [7]

Answer:

$\dfrac{x+2}{x+1}$

Step-by-step explanation:

Factor the numerator and cancel common factors from numerator and denominator.

$\dfrac{x^2-4}{(x-2)(x+1)}=\dfrac{(x-2)(x+2)}{(x-2)(x+1)}=\dfrac{x+2}{x+1}$

5 0

2 years ago

Find all values of the angle θ (in radians, with 0 ≤ θ < 2π) for which the matrix a = cos θ −sin θ sin θ cos θ has real eigen

harina [27]

The matrix

$A=\begin{bmatrix}\cos\theta&-\sin\theta\\\sin\theta&\cos\theta\end{bmatrix}$

has eigenvalues $\lambda$ such that

$\det(A-\lambda I)=\begin{vmatrix}\cos\theta-\lambda&-\sin\theta\\\sin\theta&\cos\theta-\lambda\end{vmatrix}=0$

$(\cos\theta-\lambda)^2+\sin^2\theta=0$

$(\cos\theta-\lambda)^2=-\sin^2\theta$

$\cos\theta-\lambda=\pm\sqrt{-\sin^2\theta}$

$\lambda=\cos\theta\pm\sqrt{-\sin^2\theta}$

$\sin^2\theta\ge0$ for all values of $\theta$ , so we need to have $\sin\theta=0$ in order for $\lambda$ to be real-valued. This happens for

$\sin\theta=0\implies\theta=n\pi$

where $n$ is any integer, and over the given interval we have $\theta=0$ and $\theta=\pi$ .

4 0

2 years ago

2^x - 3^x = √(6^x - 9^x)

dmitriy555 [2]

Answer to the miscellaneous equation, is x=0

Miscellaneous equation are the equations which are not polynomial.

The question can be solved by:

Factorising:Splitting the terms to find the required solution

Completing the squares, etc

2ˣ -3ˣ=√(6ˣ-9ˣ)

-> (2ˣ -3ˣ)²=(3ˣ.2ˣ - 3²ˣ)

Squaring both sides,

-> 2²ˣ+3²ˣ- 2.3ˣ.2ˣ=(3ˣ.2ˣ - 3²ˣ)

-> 2²ˣ+2.3²ˣ-2.3ˣ.2ˣ-3ˣ.2ˣ=0

Factorising the terms,

-> 2ˣ(2ˣ-3ˣ) -2.3ˣ(2ˣ-3ˣ)=0

-> (2ˣ-3ˣ)(2ˣ-2.3ˣ)=0

Equating the braces to zero,

x=0 is the only solution.

Therefore, x =0 is the only solution

Learn more about miscellaneous equation: brainly.com/question/1214333

#SPJ10

3 0

1 year ago

Read 2 more answers

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