Answer:
Approximate of error = 11.11 % (Approx.)
Step-by-step explanation:
Given:
Exact value = 50
Approximate value = 45
Find:
Approximate of error
Computation:
Approximate of error = [(Exact value - Approximate value)/Approximate value]100
Approximate of error = [(50 - 45)/45]100
Approximate of error = [(5)/45]100
Approximate of error = [0.11111]100
Approximate of error = 11.11 % (Approx.)
Answer:
Follows are the explanation to the given question:
Step-by-step explanation:
Its determination of inventory amounts for various products. Its demand is an excellent illustration of a dynamic optimization model used in my businesses. Throughout this case, its store has restrictions within this room are limited. There are only 100 bottles of beverages to be sold, for instance, so there is a market restriction that no one can sell upwards of 50 plastic cups, 30 power beverages, and 40 nutritional cokes. Throughout this situation, these goods, even the maximum quantity supplied is 30, 18, and 28. The profit for each unit is $1, $1.4, and $0.8, etc. With each form of soft drink to also be calculated, a linear extra value is thus necessary.
Answer:
n = -45
Step-by-step explanation:
(n-5) /10 = -5
Multiply each side by 10
(n-5) /10 *10= -5*10
n-5 = -50
Add 5 to each side
n-5+5 = -50+5
n = -45
The spinner is divided into four equal sections: 2, 4, 7, 9. This represents 4 possibilities
If the spinner is spun twice, the sample space is:
For product less than 30, the number of outcomes is shown below:
The number of outcomes that have a product less than 30 = 10
The sample space that shows possibilities of an odd number combination:
The number of outcomes that contains at least one odd number = 12
The number of outcomes that have a product less than 30 and contain at least one odd number is shown below. These outcomes are outcomes circled in both cases shown above,
The outcomes circled represents the number of outcomes that has a product less than 30 and contains at least one odd number
Answer: 6 (option B)
