Answer:
3 ,5 , and 2
Step-by-step explanation:
Hope it helps :)
Answer: 13&7
Step-by-step explanation:
The sum of two numbers x&y is 20
Product of the 2numbers xy is 51
X+y=20......equation 1
XY=51.........equation 2
X=20-y.......equation 3
Substitute for x inequation 3 into equation 2
So we have;
(20-y)y=51
Open the bracket
20y-y^2=51
Collect like terms,so we have
Y2-20y+51=0
Factorise
Factors of 51 is 13&7
So -13-7=-20 &-13×-7=51
Substitute
Y2-13y-7y+51=0
Y(y-13)-7(y-13)=0
(Y-7)(y-13)=0
Y-7=0
Y=7 or
Y-13=0
Y=13
Y=13 or 7
Substitute for y in equation 1
X+y=20
X+7=20
X=20-7
X=13 or
X+13=20
X=20-13
X=7
Therefore, X &Y = 13 &7
As the y value in creases so will the x value
Answer:
H. $360.71
Step-by-step explanation:
The 1 in $435.15 is in the tenths place. It has a value of 1/10. One tenth that value is 1/100. To have that value, a 1 would need to be in the hundredths place: 0.01.
Of the offered choices, the only one with a 1 in the hundredths place is ...
H. $360.71
If you add all of the numbers together the answer your going to get is 17+32+28 which equals 77
