Would use the algorithm for solving square root.
For square root, √n
x₁ = 0.5(x₀ + n/x₀)
(This formula is known and for square root, and can be derived using Newton-Raphson's approximation equation)
Where x₀ is the initial guess. x₁ becomes the new guess.
For √100.6 let our initial guess be 10, x₀ = 10, n = 100.6
Our approximation shall be to 3 decimal places. Once we get the same answer twice we stop the algorithm.
x₀ = 10, x₁ = 0.5(x₀ + n/x₀), x₁ = 0.5(10 + 100.6/10) = 10.030, x₁ = 10.030
x₂ = 0.5(x₁ + n/x₁), x = 0.5(10.030 + 100.6/10.030) ≈10.015, x₂ ≈ 10.030 (to 3 decimal places)
Since x₂≈ x₁, the algorithm stops.
So the √100.6 is ≈ 10.030 to 3 decimal places.
I hope this helps.
Hello there! ;) The way you solve this type of problem is you must find common denominators. So simplify 13/3= 4 1/3. So we can do 1/3*5/5=5/15. Next we must do 3/5*3/3= 9/15. So add 5/15+9/15= 14/15. And add the 4+ 14/15= 4 14/15. So then you must subtract 15 - 4 14/15= 10 1/15 I believe. I believe 10 1/15 is the remainder of the rope. You might want to check in with someone else though.
Hope I help! :D
Each shape has a different formula for area. rectangles and parallelograms share the same formula, A=bh
Trapezoids formula is A= 1/2(b1 + b2)h
Triangles formula is A = 1/2bh
In all of these formulas, A means area, and h means the height of the shape. In the formulas for triangles and rectangles/parallelograms, b stands for the length of the base of the shape.
In the trapezoids formula, b1 means base 1 and b2 means base two, as a trapezoid has two different bases.
After finding all of the variables for the formula of the shape you're solving for, plug all the numbers into your missing variables, and solve as normal.
7=7×1
13=13×1
Lcm=7×13
=91
