Question

Find twe positive even consecutive intecers such

Answer 1

Answer:

4 and 6

Step-by-step explanation:

x = smaller integer

x+2 = larger integer

x² = 10 + (x + 2)

x² = x + 12

x² - x - 12 = 0

factors are:

(x-4)(x+3) = 0

x-4=0;  x = 4

x+3=0;  x = -3

Since the question states the numbers are even and positive we use only the 4 and the next consecutive even integer is 6

Answer 2

Answer:

The numbers are 4 and 6

Step-by-step explanation:

Let:

• x - the smaller even consecutive integer  
• x+2 - the larger even consecutive integer

we know that

$x^{2} =(x+2)+10$

solve for x

$x^{2} -x-12=0$

We can use the quadratic formula for quadratics in the form $ax^{2} +bx+c=0$

$x= \frac{-b(+/-)\sqrt{b^{2} -4ac}}{2a}$

to give us an answer of 4 and -3

Since the question states positive and even we use 4 and that gives us 6 as the other answer
4 and 6