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velikii [3]
3 years ago
9

Plz. Help Me!! ASAP!!!!!!

Mathematics
1 answer:
PtichkaEL [24]3 years ago
3 0
-12.5%
2/1.5 =0.125 move the decimal and it become 12.5 but because it’s decreasing it is -12.5%
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20 POINTS AND BRAINLIEST
emmainna [20.7K]
To solve this equation we must first plug in 5 for x.

\frac{1}{3}<span> (5 - 4x)
               </span>↓ 
\frac{1}{3} (5 - 4 · 5)

The next step would be to multiply 4 by 5 to get rid of the parenthesis within our main parenthesis.

\frac{1}{3} (5 - 4 · 5)

\frac{1}{3} (5 - 20)

The next step would be to subtract both of the numbers within the parenthesis.

\frac{1}{3} (-15)

Now we must multiply.

- \frac{1}{3} · 15 =  - \frac{1×15}{3}

- \frac{15}{3}

Now we simplify our answer to get our final answer.

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8 0
3 years ago
HELP PLEASE 25 POINTS
erastova [34]

Answer:

$15, $8, $1, respectively

Step-by-step explanation:

Line up the number of years with the line and check the pay.

3 0
3 years ago
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Harry paid $35 for a tie and $11 for a T-shirt. He gave the cashier a 100-dollar bill. How much change did he receive from the c
Vaselesa [24]

Answer:

54

Step-by-step explanation: you add 35 and 11 together then subtract 100 by the number you got to get the anwser

4 0
2 years ago
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In a restaurant, the proportion of people who order coffee with their dinner is p. A simple random sample of 144 patrons of the
mote1985 [20]
<h2>Answer with explanation:</h2>

Given : In a restaurant, the proportion of people who order coffee with their dinner is p.

Sample size : n= 144

x= 120

\hat{p}=\dfrac{x}{n}=\dfrac{120}{144}=0.83333333\approx0.8333

The null and the alternative hypotheses if you want to test if p is greater than or equal to 0.85 will be :-

Null hypothesis : H_0: p\geq0.85   [ it takes equality (=, ≤, ≥) ]

Alternative hypothesis : H_1: p  [its exactly opposite of null hypothesis]

∵Alternative hypothesis is left tailed, so the test is a left tailed test.

Test statistic : z=\dfrac{\hat{p}-p}{\sqrt{\dfrac{p(1-p)}{n}}}

z=\dfrac{0.83-0.85}{\sqrt{\dfrac{0.85(1-0.85)}{144}}}\\\\=-0.561232257678\approx-0.56

Using z-vale table ,

Critical value for 0.05 significance ( left-tailed test)=-1.645

Since the calculated value of test statistic is greater than the critical value , so we failed to reject the null hypothesis.

Conclusion : We have enough evidence to support the claim that p is greater than or equal to 0.85.

8 0
3 years ago
The value of 8y 2 –5y +1 when y= 1 is …………​
ELEN [110]

Answer:

4

Step-by-step explanation:

8(1)^2 -5(1) +1

8(1) -5(1) +1

8 -5 +1

4

4 0
3 years ago
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