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kipiarov [429]
2 years ago
7

Solve using elimination.

Mathematics
1 answer:
dmitriy555 [2]2 years ago
8 0
The process and the answer is shown in the following picture. The five ones are all the same.

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purchasing a movie combo pack of one popcorn and two drinks for 14 saves 4 compared to purchasing the items individually. if a d
forsale [732]

Answer:

A drink is 5 so two are 10...

And original cost-if saves 4 is 18

so 18-10=8

Popcorn is 8 dollars i think

5 0
3 years ago
Read 2 more answers
HELP RN PLEASEEE for a quiz
sattari [20]

Answer:

Step-by-step explanation:

( x_{1} , y_{1} )

( x_{2} , y_{2} )

m = \frac{y_{2} -y_{1} }{x_{2} -x_{1} }

parallel lines have the same slopes , perpendicular lines have slope which are opposite reciprocals.

~~~~~~~~~~~~~~~

A( 3 , 5 )

B( - 2 , 7 )

m_{AB} = \frac{7-5}{-2-3} = - \frac{2}{5}

C( 10 , 5 )

D( 6 , 15 )

m_{CD} = \frac{15-5}{6-10} = - \frac{5}{2}

The answer is (A) Neither

8 0
2 years ago
I really need this please don’t answer it wrong!
enyata [817]

Answer:

Step-by-step explanation:

Squaring a^(-2) results in a^(-4).

Squaring 8^7 results in 8^14.

Putting these factors together, we get

8^14

-------                     this is equivalent to Answer C.

a^4

5 0
3 years ago
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A bag contains 20 pieces of candy. There are 8 grape peices, 7 cherry pieces, and 5 lemon pieces. part a says that one piece is
Alex787 [66]
Grape- 8/20 = 2/5 = 40%
cherry - 7/20 = 35%
lemon - 5/20 = 25%
5 0
3 years ago
Provide an appropriate response.
oksian1 [2.3K]
You don't even have to look up the definition of 'standard deviation'.  You only
have to remember that 'smaller standard deviation' means 'less spread-out'.

First, let's find the mean (average).  It's not supposed to change:

1/7th of (65 + 71 + 77 + 80 + 82 + 90 + 96) = 561/7 = <u>80 and 1/7</u> .

Now, just pick 7 scores that total 561 and are all bunched up.

The easiest way would be 80, 80, 80, 80, 80, 80, 81 .
But that's so easy that it feels like cheating.

Let's say <u>77, 78, 79, 80, 81, 82, and 84</u> .
8 0
3 years ago
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