Given the domain {-4, 0, 5}, what is the range for the relation 12x 6y = 24? a. {2, 4, 9} b. {-4, 4, 14} c. {12, 4, -6} d. {-12,
xz_007 [3.2K]
The domain of the function 12x + 6y = 24 exists {-4, 0, 5}, then the range of the function exists {12, 4, -6}.
<h3>How to determine the range of a function?</h3>
Given: 12x + 6y = 24
Here x stands for the input and y stands for the output
Replacing y with f(x)
12x + 6f(x) = 24
6f(x) = 24 - 12x
f(x) = (24 - 12x)/6
Domain = {-4, 0, 5}
Put the elements of the domain, one by one, to estimate the range
f(-4) = (24 - 12((-4))/6
= (72)/6 = 12
f(0) = (24 - 12(0)/6
= (24)/6 = 4
f(5) = (24 - 12(5)/6
= (-36)/6 = -6
The range exists {12, 4, -6}
Therefore, the correct answer is option c. {12, 4, -6}.
To learn more about Range, Domain and functions refer to:
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Answer:
15 R7
Step-by-step explanation:
<u> 015</u>
32/ 487
<u>0</u>
48
<u>32</u>
167
<u>160</u>
remainder 7
Answer:
1 solution
Step-by-step explanation:
A system of linear equations has no solution when the graphs are parallel.
Answer:
83 1/3 words per minute
or approximately 83 words per minute
Step-by-step explanation:
4 pages * 250 words/ page = 1000 words
1/5 hour * 60 minutes/ 1 hour = 12 minutes
1000 words / 12 minutes = 83.333333333.... words per minute
83 1/3 words per minute
<h3>Factor</h3><h3>√x²+5x+3+2x²+10x-15=0</h3><h3>√x²+2x²+5x+10x+3-15=0</h3><h3>√3x²+15x-12=0</h3><h3>√3x²+(3(5x)+3×-4=0</h3><h3>√3(x²+5x)+3×-4=0</h3><h3>√3(x²+5x-4)=0</h3><h3> </h3>
please mark this answer as brainlist
