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Gnoma [55]
2 years ago
13

17) At the beginning of a winter storm, Sean

Mathematics
1 answer:
barxatty [35]2 years ago
3 0

Answer:

it dropped 20°F

Step-by-step explanation: since its at -2°F, u subtract 18°F to get 0°F. Then you subtract another 2°F to get -2°F. hope this helped. Its pretty simple.

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Two groups collect litter along the side of a rode. It takes each group 5 min to clean up a 200-yard section. How long does it t
abruzzese [7]
The answer is 1 hr 28 min. picture included for work. there are other ways to solve this

6 0
3 years ago
Help with these questions Please :(
attashe74 [19]
The angle of YWZ is equal to the angle of YWX, and angle WYX is also a right angle due to the congruency of segments WZ and WX.

Every triangle has an angle total of 180 degrees, so angle WXY is equal to

180 - (WYX + YWX)
180 - (90 + 17)
73

Angle WXY has an angle value of 73 degrees.
8 0
3 years ago
Question 5 :)) What is the measure of the missing angle?​
Stella [2.4K]
The answer is 115 because the interior angle is 65 and 115 plus 65 is 180. You want 180 because the angles are opposite and make a straight line
6 0
2 years ago
2x² - 5x+1 has roots alpha and beta. Find alpha⁴+beta⁴ without solving the equation.
shepuryov [24]

Answer:

Step-by-step explanation:

\alpha+\beta=\dfrac{5}{2} \\\\\alpha*\beta=\dfrac{1}{2} \\\\\alpha^2+\beta^2=\dfrac{21}{4} \ (see\ previous\ post)\\\\(\alpha+\beta)^4=\dfrac{625}{16} \\\\=\alpha^4+\beta^4+4*\alpha^3*\beta+6*\alpha^2*\beta^2+4*\alpha*\beta^3\\\\=\alpha^4+\beta^4+4*(\alpha*\beta)(\alpha^2+\beta^2)+6*\alpha^2*\beta^2\\\\\alpha^4+\beta^4=(\alpha+\beta)^4-4*(\alpha*\beta)(\alpha^2+\beta^2)-6*\alpha^2*\beta^2\\\\= \dfrac{625}{16} -4*\dfrac{1}{2} *\dfrac{21}{4} -6*(\dfrac{1}{2})^2 \\\\

= \dfrac{625}{16}- \dfrac{168}{16}-\dfrac{24}{16}\\\\\\= \dfrac{433}{16}

7 0
3 years ago
If J is the centroid of cde, de=52, fc=15, he=14, find each missing measure
const2013 [10]

Answer:

DG = 26

GE = 26

DF = 15

CH = 14

CE = 28

Step-by-step explanation:

The figure has been attached, to complement the question.

DE = 52

FC = 15

HE = 14

Given that J is the centroid, it means that J divides sides CD, DE and CE into two equal parts respectively and as such the following relationship exist:

DF = FC

CH = HE

DG = GE

Solving (a): DG

If DG = GE, then

DE = DG + GE

DE = DG + DG

DE = 2DG

Make DG the subject

DG = \frac{1}{2}DE

Substitute 52 for DE

DG = \frac{1}{2} * 52

DG = 26

Solving (b): GE

If DG = GE, then

GE = DG

GE = 26

Solving (c): DF

DF = FC

So:

DF = 15

Solving (d): CH

CH = HE

CH = 14

Solving (e): CE

If CH = HE, then

CE = CH + HE

CE = 14 + 14

CE = 28

7 0
3 years ago
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