Answer:
Step-by-step explanation:
When Riko left his house, Yuto was 5.25 miles along the path.
Average speed of Riko = 0.35 miles per minute
Average speed of Yuto = 0.25 miles per minute
First we will calculate the time in which Riko will catch Yuto on the track.
Relative velocity of Riko as compared to Yuto will be = velocity of Riko - velocity of Yuto
= 0.35 - 0.25
= 0.10 miles per minute
Now we this relative velocity tells that Riko is moving and Yuto is in static position.
By the formula,
Average speed = ![\frac{Distance}{Time}](https://tex.z-dn.net/?f=%5Cfrac%7BDistance%7D%7BTime%7D)
0.10 = ![\frac{5.25}{t}](https://tex.z-dn.net/?f=%5Cfrac%7B5.25%7D%7Bt%7D)
t = ![\frac{5.25}{0.1}](https://tex.z-dn.net/?f=%5Cfrac%7B5.25%7D%7B0.1%7D)
t = 52.5 minutes
Now we know that Rico will catch Yuto in 52.5 minutes. Before this time he will be behind Yuto.
So duration of time in which Rico is behind Yuto will be 0 ≤ t ≤ 52.5
Here time can not be less than zero because time can not be with negative notation. It will always start from 0.
Answer= 70.7 meters.
Step-by-step explanation:
We have been given that Elise walks diagonally from one corner of a square plaza to another. Each side of the plaza is 50 meters.
Since we know that diagonal of a square is product of side length of square and . So we will find diagonal of our given square plaza by multiplying 50 by .
Therefore, diagonal distance across the plaza is 70.7 meters.
Answer: 26 13/30 feet
Step-by-step explanation:
The hall is in the shape of a rectangle. The perimeter of a rectangle is:
= 2(length + width)
= 2l + 2w
Since perimeter = 71 2/3 ft and Width = 9 2/5 ft wide, the length will be calculated thus:
Perimeter = 2l + 2w
71⅔ = 2l + 2(9 2/5)
71 2/3 = 2l + (2 × 47/5)
71 2/3 = 2l + 94/5
71 2/3 = 2l + 18 4/5
Collect like terms
2l = 71 2/3 - 18 4/5
2l = 71 10/15 - 18 12/15
2l = 52 13/15
l = (52 13/15 ÷ 2)
l = 793/15 × 1/2
l = 793/30
l = 26 13/30
Therefore, the length is 26 13/30ft
Answer:
8
Step-by-step explanation:
5-(-3)=8
|8|=8