We add 548 and 225 which would be 773
Answer:
a) There is not sufficient evidence to support the claim that the mean attendance is greater than 642.
Step-by-step explanation:
since in the question it is mentioned that the average attendance at games should be more 642 and according to this he moving the team with a larger stadium. Also the hypothesis conducted and the conclusion would be failure to deny the null hypothesis
So here the conclusion that should be made in non-technical term is that there should be no enough proof in order to support the claim that the mean attendence is more than $642
When the diagonals of a quadrilateral are perpendicular, the area of that quadrilateral is half the product of their lengths.
.. A = (1/2)*d₁*d₂
Substituting the given information, this becomes
.. 58 in² = (1/2)*(14.5 in)*d₂
.. 2*58/14.5 in = d₂ = 8 in
The length of diagonal BD is 8 in.
Answer:
50 dollors
Step-by-step explanation:
When we take data at work, we always do it over a period of time. To me, just one sample set does not show enough data to come to that conclusion. Also it is one batch of bags. I think you would need to have an average of data from different batches & samples to prove your data is accurate and support your claim.