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madreJ [45]
3 years ago
15

How many triangles can be constructed with sides measuring 5 m, 16 m, and 5 m?

Mathematics
1 answer:
lianna [129]3 years ago
3 0
There are two measures 5 cm then the triangle will be isosceles or 16 is far beyond 5 + 5 = 10 so we cannot build any triangle so te answer is <span>B none
</span>
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Because the three sides are congruent, what foes that make each angle measure according to the equilateral triangle theorem.
m_a_m_a [10]
Answer : 60 degrees
Explanation: All triangles's angles add up to 180. Since all angles are equal, you can divide 180 by 3. 180/3 is 60
3 0
3 years ago
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Tom is the deli manager at a grocery store.He needs to schedule employees to staff the deli department at least 260 person-hours
Drupady [299]
I hope this is right but:
Let n=number of full time employees

260<=20+n*40
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240<=n*40
n>=240/40
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Though I'm not sure if the attached file is the graph you are looking for 

4 0
3 years ago
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damaskus [11]

<u>ANSWER:  </u>

x-intercepts of  \mathrm{x}^{2}+12 \mathrm{x}+24=0 \text { are }(-6+2 \sqrt{3}),(-6-2 \sqrt{3})

<u>SOLUTION:</u>

Given, f(x)=x^{2}+12 x+24 -- eqn 1

x-intercepts of the function are the points where function touches the x-axis, which means they are zeroes of the function.

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X=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}

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X=\frac{-(12) \pm \sqrt{(12)^{2}-4 \times 1 \times 24}}{2 \times 1}

\begin{array}{l}{X=\frac{-12 \pm \sqrt{144-96}}{2}} \\\\ {X=\frac{-12 \pm \sqrt{48}}{2}} \\\\ {X=\frac{-12 \pm \sqrt{16 \times 3}}{2}} \\\\ {X=\frac{-12 \pm 4 \sqrt{3}}{2}} \\ {X=\frac{2(-6+2 \sqrt{3})}{2}, \frac{2(-6-2 \sqrt{3})}{2}} \\\\ {X=(-6+2 \sqrt{3}),(-6-2 \sqrt{3})}\end{array}

Hence the x-intercepts of  \mathrm{x}^{2}+12 \mathrm{x}+24=0 \text { are }(-6+2 \sqrt{3}),(-6-2 \sqrt{3})

8 0
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Anastaziya [24]

Answer:

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Step-by-step explanation:

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7 0
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AlexFokin [52]
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