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hoa [83]
2 years ago
14

Write the vector YZ in component form. Y(-9, 2) Z(3, -4)

Mathematics
1 answer:
Temka [501]2 years ago
6 0

Answer:

\displaystyle \overrightarrow{YZ} = \

General Formulas and Concepts:
<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

<u>Algebra I</u>

Coordinate Planes

  • Coordinates (x, y)

<u>Pre-Calculus</u>

Vectors

  • Component Form: \displaystyle \overrightarrow{XY} = \

Step-by-step explanation:

<u>Step 1: Define</u>

<em>Identify.</em>

Point Y(-9, 2)

Point Z(3, -4)

<u>Step 2: Find</u>

  1. Substitute in points [Vector Component Form]:                                        \displaystyle \overrightarrow{YZ} = \
  2. [Order of Operations] Evaluate:                                                                  \displaystyle \overrightarrow{YZ} = \
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Answer:

16 x²

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3 years ago
Find a equation of a line that is perpendicular to y=-4x+3 and passes through the point (4,-1).
Marina86 [1]

Given:

The given equation is:

y=-4x+3

A line is perpendicular to the given line and passes through the point (4,-1).

To find:

The equation of required line.

Solution:

The slope intercept form of a line is:

y=mx+b

Where, m is slope and b is y-intercept.

We have,

y=-4x+3

Here, the slope of the line is -4 and the y-intercept is 3.

Let the slope of required line be m.

We know that the product of slopes of two perpendicular lines is -1. So,

m\times (-4)=-1

m=\dfrac{-1}{-4}

m=\dfrac{1}{4}

The slope of required line is m=\dfrac{1}{4} and it passes through the point (4,-1). So, the equation of the line is:

y-(-1)=\dfrac{1}{4}(x-4)

y+1=\dfrac{1}{4}(x)-\dfrac{4}{4}

y=\dfrac{1}{4}x-1-1

y=\dfrac{1}{4}x-2

Therefore, the equation of the required line is y=\dfrac{1}{4}x-2.

5 0
2 years ago
After rectangle WXYZ is translated 4 units to the left, what are the coordinates of X’?
Blizzard [7]

Answer:

4,2

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
What is the distance between –125 and 78?
nexus9112 [7]
The disstance between -125 and 78 is 47
8 0
3 years ago
Mr. Dey took out Rs.5000 from his bank. He took 40 notes of 50 Rupees each and the remaining amount in 20 Rupees notes. How many
MrRa [10]

Answer:

150

Step-by-step explanation:

Start with Rs.5000.

40 notes of 50 Rupees each = 40 * Rs.50 = Rs.2000

Rs.5000 - Rs.2000 = Rs.3000

He took Rs.3000 in 20 Rupees notes.

Rs.3000/Rs.20 = 150

Answer: He took 150 20-Rupee notes

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3 years ago
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