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Juliette [100K]
3 years ago
14

a city stores fresh water in a spherical tank. The tank has a radius of 32 feet. One cubic foot is approximately 7.5 gallons. If

the city drains 140,000 gallons of water out of the full tank, how many gallons are left in the tank. Round your answer to the nearest gallon.
Mathematics
1 answer:
Serjik [45]3 years ago
6 0
Answer: There will be about 888,915 gallons of water left in the spherical tank.

First, we need to determine the volume of the tank. The volume formula for a sphere is (4/3)pi(r^3). All we have to do is input the 32 for pi and evaluate. You will have a volume of 137,189 cubic feet.

Now, multiply that by 7.5 and you will have 1,028,915 gallons of water in the tank.

Finally, just subtract the 140,000 gallons and we are at our answer.
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The volume of a cube is the cube of the length of a side. If a side is S, the volume is S^3. What is the volume of a cube with s
sergij07 [2.7K]

Volume is a three-dimensional scalar quantity. The volume of the cube with side length of 4 inches is 64 inches³.

<h3>What is volume?</h3>

A volume is a scalar number that expresses the amount of three-dimensional space enclosed by a closed surface.

Given the volume of a cube is the cube of the length of a side. If a side is S, the volume is S^3. Therefore, the volume of cube with side 4 inches will be,

Volume of the cube = (4 in)³ = 64 in³

Hence, the volume of the cube with side length of 4 inches is 64 inches³.

Learn more about Volume:

brainly.com/question/13338592

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6 0
2 years ago
Use the information provided to determine a 95% confidence interval for the population variance. A researcher was interested in
Leno4ka [110]

Answer:

The 95% confidence interval for the population variance is (8.80, 32.45).

Step-by-step explanation:

The (1 - <em>α</em>)% confidence interval for the population variance is given as follows:

\frac{(n-1)\cdot s^{2}}{\chi^{2}_{\alpha/2}}\leq \sigma^{2}\leq \frac{(n-1)\cdot s^{2}}{\chi^{2}_{1-\alpha/2}}

It is provided that:

<em>n</em> = 20

<em>s</em> = 3.9

Confidence level = 95%

⇒ <em>α</em> = 0.05

Compute the critical values of Chi-square:

\chi^{2}_{\alpha/2, (n-1)}=\chi^{2}_{0.05/2, (20-1)}=\chi^{2}_{0.025,19}=32.852\\\\\chi^{2}_{1-\alpha/2, (n-1)}=\chi^{2}_{1-0.05/2, (20-1)}=\chi^{2}_{0.975,19}=8.907

*Use a Chi-square table.

Compute the 95% confidence interval for the population variance as follows:

\frac{(n-1)\cdot s^{2}}{\chi^{2}_{\alpha/2}}\leq \sigma^{2}\leq \frac{(n-1)\cdot s^{2}}{\chi^{2}_{1-\alpha/2}}

\frac{(20-1)\cdot (3.9)^{2}}{32.852}\leq \sigma^{2}\leq \frac{(20-1)\cdot (3.9)^{2}}{8.907}\\\\8.7967\leq \sigma^{2}\leq 32.4453\\\\8.80\leq \sigma^{2}\leq 32.45

Thus, the 95% confidence interval for the population variance is (8.80, 32.45).

4 0
3 years ago
{(1,2),(3,4),(5,6),(7,8),(9,0)}
Jobisdone [24]
The domain is (1,3,5,7,9) and the range is (2,4,6,8,0)
4 0
3 years ago
An Xbox that normally sells for $390 is on sale at a 30% discount. What is the sale price of the Xbox?
schepotkina [342]
$273 as 390×(1-30%)=273
8 0
3 years ago
In the graphic below,
sukhopar [10]

The external angle is suplementary to the internal angle close to it. We also know that the sum of all the internal angles of the triangle are equal to 180 degrees, this means that the angle "a" is suplementary to the sum of the angles "b" and "c". Through this logic, we can conclude that since:

\begin{gathered} \angle d=180-\angle a \\ \angle b+\angle c=180-\angle a \end{gathered}

Then we can conclude that:

\angle d=\angle b+\angle c

Therefore the statement is true, the exterior angle is equal to the sum of its remote interior angles.

Let's use an example:

On this example, the external angle is 120 degrees, therefore the sum of the remote interior angles must also be equal to that. Let's try:

x=75+45=120

The sum of the remote interior angles is equal to the external angle.

6 0
1 year ago
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