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Alenkinab [10]
3 years ago
6

Pro Golf Driving Range has two membership options to choose from. Option A includes an initial

Mathematics
1 answer:
murzikaleks [220]3 years ago
6 0

Answer: B

Step-by-step explanation: option B would be a better deal than option a because if you go off went golfing and use option a every month and paid $25 It would add up to $85 a month so it’s better to do b and option a would be a better deal if you only went golfing one time a month. I hope this makes sense!

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How to solve this problem​
nevsk [136]

Let C be the center of the circle. The measure of arc VSU is 2+114x, so the measure of the minor arc VU is 360-(2+114x)=358-114x. The central angle VCU also has measure 358-114x.

Triangle CUV is isosceles, so the angles CVU and CUV are congruent. The interior angles of any triangle are supplementary (they add to 180 degrees) so

m\angle VCU+2m\angle CUV=180

\implies m\angle CUV=\dfrac{180-(358-114x)}2=57x-89

UT is tangent to the circle, so CU is perpendicular to UT. Angles CUV and VUT are complementary, so

(57x-89)+(31x+3)=90

\implies88x=176

\implies x=2

So finally,

m\widehat{VSU}=2+114\cdot2=230

degrees.

6 0
3 years ago
1. Carlos has $1,800 in a checking account set aside for summer expenses.
Free_Kalibri [48]

Answer:2 weeks

Step-by-step explanation: if you subtract 1800 by 150 for the two weeks you will get 1500 and if you add 1100 by 200 every week you will get a hundred and fifty

4 0
3 years ago
L=4m\n+p solve for p
Anastasy [175]
I think the correct answer would be : p = -n+4m/L
I hope this helps !
7 0
3 years ago
Find the least common multiple of 8c4 and 6c2 .
Ksju [112]
The least common multiple is the smallest term that can be divided to both terms without any remainder. For the two terms 8c^4 and 6c^2, you can determine it into two part. First, you find the LCM for 8 and 6. You find the prime number that is common between the two. That would be 2. For the variables c^4 and c^2, the 'prime variable' is c. Therefore, the least common multiple for 8c^4 and 6c^2 is 2c.
6 0
3 years ago
A shoreline is eroding at a rate of 13 foot per 3 months. How many feet are eroding per year?
gregori [183]

Answer:

52

Step-by-step explanation:

13 * 4 = 52

(is * 4 since 4 * 3 months is a year)

4 0
3 years ago
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