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professor190 [17]
3 years ago
15

Please help me with these questions (: Ty

Mathematics
1 answer:
vichka [17]3 years ago
4 0
1 = -4.5
2 = a
it's making me put 20 characters to answer this so ignore all this nonsense
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I NEED HELP GUYS PLEASE!!!! AP STATISTICS
julsineya [31]

Just count how many times a given age appears in the data. If my eyes aren't deceiving me, I count

• 26: 3

• 27: 5

• 28: 5

• 29: 5

• 30: 2

• 31: 1

• 33: 4

Then the second most frequent age in the data is 33, and the least frequent is 31.

6 0
3 years ago
A company produces widgets in three factories, A, B and C. Factory A produces 20% of the widgets, factory B produces 45% of the
agasfer [191]

Answer:

1.25% widgets from factory A fail.

Step-by-step explanation:

Probability of widgets that fail = 0.05

Probability of failing widget to belong from factory A = 0.25

Probability of failing widget to belong from factory B = 0.35

Probability of failing widget to belong from factory C = 0.40

Probability of factory A widgets failing = Probability of widgets failing * probability they belonged from factory A

Probability of factory A widgets failing = 0.05 * 0.25 = 0.0125

This probability stated as percentage: 1.25%

6 0
3 years ago
Sally's rent is $50 she has two roommates that split the rent how much do all three have to pay for rent
grandymaker [24]

Answer:

16.6

Step-by-step explanation:

50/3 = 16.6

5 0
4 years ago
You are testing a claim and incorrectly use the normal sampling distribution instead of the​ t-sampling distribution. Does this
Keith_Richards [23]

Answer:

From the given data, the typical appropriation is utilized rather than t distribution for testing. The thicknesses of the curve similarly influence both normal distribution and territory of t distribution. The normal distribution test and t test give a similar dismissal for the invalid theory for any tail of the test. Besides, the tests normal sampling distribution and t sampling distribution give a similar dismissal to null hypothesis.  

Along these lines, the outcomes got by utilizing normal distribution and t distribution are distinguished as same and for each situation, the tail thickness doesn't influence the event of the basic qualities.

8 0
3 years ago
Read 2 more answers
Which expression is equivalent to the expression below? StartFraction m + 3 Over m squared minus 16 EndFraction divided by Start
Kamila [148]

Option B: \frac{1}{(m-4)(m-3)} is the correct answer.

Explanation:

The given expression is \frac{(\frac{m+3}{m^2-16}) }{(\frac{m^2-9}{m+4} )}

Simplifying the expression, we have,

\frac{m+3}{m^{2}-16}\times\frac{m+4}{m^2-9}

Factor the equations, m^{2}-16\right and m^{2}-9,we get,

m^{2}-16\right=m^{2}-4^{2}=(m+4)(m-4)

m^{2}-9=m^{2}-3^2=(m+3)(m-3)

Substituting these factored expressions in the above expression, we have,

\frac{m+3}{(m+4)(m-4)}\times\frac{m+4}{(m+3)(m-3)}

Cancelling the common terms m+3 and m+4 , we get,

\frac{1}{(m-4)(m-3)}

Thus, the expression equivalent to \frac{(\frac{m+3}{m^2-16}) }{(\frac{m^2-9}{m+4} )} is \frac{1}{(m-4)(m-3)}

Hence, Option B is the correct answer.

3 0
3 years ago
Read 2 more answers
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