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3 years ago

Help, please, I don't understand math that well and really wanna pass this year

Mathematics

1 answer:

Harman [31]3 years ago

6 0

55.5 (the outside angle is going to be half of the inside angle if it’s on the center point)

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Evaluate the numericial expression (32 - 20) ÷ 4

SashulF [63]

Answer:

Step-by-step explanation:

(32-20)÷4

solve perentisis first

(12)÷4

now divide

3 0

3 years ago

Read 2 more answers

Write a proportion that could be used to solve for each variable. Then solve.

mamaluj [8]

There are 6 balls to every box (a ratio of 6 to 1). Therefore, when there are 78 balls, there are 13 boxes.

5 0

3 years ago

Read 2 more answers

If a/b < c/d with b > 0, d > 0, prove that a+c / b+d lies between the two fractions a/b and c/d .

Tems11 [23]

Divide through everything by b :

$\dfrac{a+c}{b+d} = \dfrac{\dfrac ab + \dfrac cb}{1 + \dfrac db}$

Since a/b < c/d, it follows that

$\dfrac{a+c}{b+d} < \dfrac{\dfrac cd+\dfrac cb}{1 + \dfrac db}$

Multiply through everything on the right side by b/d to get

$\dfrac{a+c}{b+d} < \dfrac{\dfrac{bc}{d^2}+\dfrac cd}{\dfrac bd+1} = \dfrac{\dfrac cd\left(\dfrac bd+1\right)}{\dfrac bd+1} = \dfrac cd$

and so (a + c)/(b + d) < c/d.

For the other side, you can do something similar and divide through everything by d :

$\dfrac{a+c}{b+d} = \dfrac{\dfrac ad + \dfrac cd}{\dfrac bd + 1}$

and a/b < c/d tells us that

$\dfrac{a+c}{b+d} > \dfrac{\dfrac ad + \dfrac ab}{\dfrac bd + 1}$

Then

$\dfrac{a+c}{b+d} > \dfrac{\dfrac ab + \dfrac{ad}{b^2}}{1 + \dfrac db} = \dfrac{\dfrac ab\left(1+\dfrac db\right)}{1 + \dfrac db} = \dfrac ab$

and so (a + c)/(b + d) > a/b.

Then together we get the desired inequality.

5 0

3 years ago

Answer this question please; number 5... show all work thank you

My name is Ann [436]

Answer:

rate of the plane in still air is 33 miles per hour and the rate of the wind is 11 miles per hour

Step-by-step explanation:

We will make a table of the trip there and back using the formula distance = rate x time

d = r x t

there

back

The distance there and back is 264 miles, so we can split that in half and put each half under d:

d = r x t

there 132

back 132

It tells us that the trip there is with the wind and the trip back is against the wind:

d = r x t

there 132 = (r + w)

back 132 = (r - w)

Finally, the trip there took 3 hours and the trip back took 6:

d = r * t

there 132 = (r + w) * 3

back 132 = (r - w) * 6

There's the table. Using the distance formula we have 2 equations that result from that info:

132 = 3(r + w) and 132 = 6(r - w)

We are looking to solve for both r and w. We have 2 equations with 2 unknowns, so we will solve the first equation for r, sub that value for r into the second equation to solve for w:

132 = 3r + 3w and

132 - 3w = 3r so

44 - w = r. Subbing that into the second equation:

132 = 6(44 - w) - 6w and

132 = 264 - 6w - 6w and

-132 = -12w so

w = 11

Subbing w in to solve for r:

132 = 3r + 3(11) and

132 = 3r + 33 so

99 = 3r and

r = 33

7 0

3 years ago

Can some one help me. btw the answer is not C.

Anit [1.1K]

Answer:

Step-by-step explanation:

Given

x² + 6x

To complete the square

add ( half the coefficient of the x- term )² to x² + 6x

x² + 6x + (3)²

= x² + 6x + 9

= (x + 3)²

3 0

3 years ago