The number of pretzels that must be sold to maximize the profit is 400.
<h3>What is the number of pretzels to be sold in the quadratic equation?</h3>
The number of pretzels to be sold can be determined by taking the derivative of the quadratic equation.
Given that:
P(x) = -4x^2+3200x-100
P'(x) = -8x + 3200
P''(x) = -8
At the critical point;
P'(x) = 0
Thus;
8x = 3200
x = 3200/8
x = 400
P''(400) = -8
P'' (400) < 0
Therefore, at x = 400, P(x) will be maximum.
Learn more about calculating the derivative of a quadratic equation here:
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Answer:
104 ft Squared
Step-by-step explanation:
You are taking away the room area. So 11x10=110 (Area of the whole wall) and you are cutting off 3x2=6 (Area of the wall you are cutting off). So you subtract 110-6= 104 ft2.
First number = x
second number = x-3
third number = 2x
x + x-3 + 2x = 53
4x -3 =53
4x -3+3 =53+3
4x = 56
4x/4 = 56/4
x = 14
first number = 14
second number = 14-3
second number = 11
third number = 2x
third number = 2(14)
third number = 28
14 + 11 +28 = 53
53=53
Answer:
C
Step-by-step explanation:
Answer:
u= -2w/3 + 4/3.
Step-by-step explanation:
Subtract 13 from both sides
-12u = 8w -16
Multiply both sides by -1/12.