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2 years ago

Y=(x-5)(x+1). What is the vertex of the parabola

Mathematics

1 answer:

dedylja [7]2 years ago

5 0

Answer:

Rewrite in vertex form and use this form to find the vertex

(h , k ) . ( 2 , − 9 )

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Factorize the following expression ab-a-b+1

dolphi86 [110]

Group 'em together

a b − a + 1 − b

a b − a = a ( b − 1 )

Notice that there will be a 1 as without it it'll simply be ab

1 − b = 1 ( 1 − b )

Notice that it doesn't match with the upper one... so we'll change the signs

1 ( 1 − b ) = − 1 ( b− 1 )

(try to multiply them now!!

Jot them down in one expression

a ( b − 1 ) − 1 ( b − 1 )

You get!!!!!!

( a − 1 ) ( b − 1 )

5 0

2 years ago

The volume of cube is 343 cubic centimeters.What is the suface area of the cube

Ann [662]

The cube root of 343 is 7.
One side has an area of 7*7 = 49 square cm
There are 6 sides to a cube
6 * 49 is the surface area = 294

7 0

3 years ago

What is the slope-intercept form of the equation for the line?

mart [117]

Answer:

(-4, 2) and (4, -5)

m = (-5 - 2)/(4 - (-4)) = -7/8

y = -7/8 * (x - (-4)) + 2

y = -7/8 * (x + 4) + 2

y = -7/8 * x - 3/2

8 0

2 years ago

What is x, the angle at which the diagonal beam meets the

givi [52]

Answer:16.7

Step-by-step explanation:

5 0

2 years ago

Read 2 more answers

A basketball team has 10 players. Before each game, the coach picks 2 of those players to carry the team's

labwork [276]

The different group of 2 players that the coach can pick is 45 groups.

<h3>Selection of groups</h3>

The selection of groups of 2 player can be done using the method of combination.

<h3>Different groups of 2 players</h3>

The different group of 2 players that the coach can pick from the 10 players is calculated as follows;

n = 10C2

$n = \frac{10!}{(10-2)! 2!} = \frac{10 \times 9\times 8!}{8! \times 2} = 45$

Thus, the different group of 2 players that the coach can pick is 45 groups.

Learn more about combinations here: brainly.com/question/25821700

6 0

1 year ago