If A and B are equal:
Matrix A must be a diagonal matrix: FALSE.
We only know that A and B are equal, so they can both be non-diagonal matrices. Here's a counterexample:
![A=B=\left[\begin{array}{cc}1&2\\4&5\\7&8\end{array}\right]](https://tex.z-dn.net/?f=A%3DB%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D1%262%5C%5C4%265%5C%5C7%268%5Cend%7Barray%7D%5Cright%5D)
Both matrices must be square: FALSE.
We only know that A and B are equal, so they can both be non-square matrices. The previous counterexample still works
Both matrices must be the same size: TRUE
If A and B are equal, they are literally the same matrix. So, in particular, they also share the size.
For any value of i, j; aij = bij: TRUE
Assuming that there was a small typo in the question, this is also true: two matrices are equal if the correspondent entries are the same.
Hello!
To factor you find the biggest number they can be divided by
The biggest number that all the number can be divided by is 10
You put that outside parenthesis
10()
Divide the expression by 10
3 + x - 4y
Put the two together
10(3 + x + 4y)
Hope this helps!
The domain the given graph is :
- -12 <u><</u> x <u><</u> 13
Based on the reflexive property of congruency, the missing step in the proof is: A. ∠ABC ≅ ∠DBE
<h3>What is the
Reflexive Property of Congruency?</h3>
The reflexive property of congruency states that an angle will always be congruent to itself.
In the diagram given, we can prove that ∠ABC ≅ ∠DBE based on the reflexive property.
Therefore, the missing step in nthe proof is: A. ∠ABC ≅ ∠DBE
Learn more about reflexive property on:
brainly.com/question/1601404
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