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1 year ago

What would step 3 look like after you have added the two equations?

Mathematics

1 answer:

Elenna [48]1 year ago

8 0

$\begin{gathered} 8x-10y=20 \\ -8x-6y=-4 \\ -16y=16 \end{gathered}$

Adding the two equations will be adding similar terms to both equations. That is:

8x + (-8x) = 0

-10y + (-6y) = -16y

20 + (-4) = 16

Therefore, adding the two equations will look like -16y = 16. (Option 3)

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Solve for x in the picture please

Nutka1998 [239]

Answer: $x=1$

Step-by-step explanation:

In order to find the value of "x", it is important to remember that:

$Tangent\ chord\ angle=\frac{1}{2}(Intercepted\ arc)$

We can identify in the figure that:

$Tangent\ chord\ angle=(43x)\°\\\\Intercepted\ arc=AB$

Then:

$43x=\frac{1}{2}AB$

Solving for AB:

$2(43x)=AB\\\\AB=86x$

Now, since there are 360° in a circle, we know that:

$AB+(272x+2)=360$

Then we can substitute $AB=86x$ into $AB+(272x+2)=360\°$ and solve for "x". This is:

$(86x)+(272x+2)=360\\\\358x=360-2\\\\x=\frac{358}{358}\\\\x=1$

8 0

3 years ago

2^x+5 = 3^1-x use logarithms to solve the exponential equation. round answer to 3 decimal places.

marysya [2.9K]

$2^{x+5}=3^{1-x}\ \ \ \ \ /log_2()\\\\log_22^{x+5}=log_23^{1-x}\\\\x+5=(1-x)log_23\\\\x+5=log_23-xlog_23\\\\x+xlog_23=log_23-5\\\\x(1+log_23)=log_23-5\ \ \ \ /:(1+log_23)$

$x=\frac{log_23-5}{1+log_23}\\-------------\\log_23\approx1.5849625\\----------------\\x\approx\frac{1.5849625-5}{1+1.5849625}\approx-1.321$

8 0

3 years ago

Read 2 more answers

Which of the following numbers could be the sides of a right triangle. A)8,15,17. B)6,8,12 C)9,11,21 D)4,13,16

ArbitrLikvidat [17]

Answer:

A) 8, 15, 17.

Step-by-step explanation:

Right triangle obey the Pythagorean theorem. Thus, we choose the two smaller numbers (being the cathetus) and if after applying the P. Theorem we get the biggest of each option (the hypotenuse) that means that those numbers could be the sides of a right triangle.

The Pythagorean theorem states that: $a^2+b^2=c^2$